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murzikaleks [220]
2 years ago
12

Suggest two ways in which the boy could balance the beam?

Physics
2 answers:
Oduvanchick [21]2 years ago
7 0
He can balance it on his hand or look for something that can handle the weight of it
postnew [5]2 years ago
5 0

Answer:

Hope this is what you were looking for!

Explanation:

1) So, if we are talking about balancing a straight stick (beam), he could put a finger from each hand on either side of it and move them together. As a result of friction his fingers will meet at the balance point.

2) Method of trial and error.

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Calculate the force between two objects that have
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\text { The force between the given two objects is } 1.865 \times 10^{-6} \mathrm{N}

<u>Explanation</u>:

As per given question,

m_{1} \text { is } 140 \mathrm{kg}

m_{2} \text { is } 160 \mathrm{kg}

R is 0.895 m

The force between two objects is  

\mathrm{F}=\frac{G m_{1} m_{2}}{R^{2}}

Where,

F is the force of attraction between two objects in Newton’s (N)

\text { G is the Universal Gravitational Constant }=6.674 \times 10^{-11} \mathrm{N}-\mathrm{m}^{2} / \mathrm{kg}^{2}

m_{1} \text { and } m_{2} \text { are the masses of the two objects in kilograms (kg) }

R is the separation in meters (m) between the objects

Substitute the given values in the above formula,

F=\frac{6.674 \times 10^{-11} \times 140 \times 160}{0.895^{2}}

F=\frac{1.494 \times 10^{-6}}{0.801}

\mathrm{F}=1.865 \times 10^{-6}

\text { The force between the given two objects is } 1.865 \times 10^{-6} \mathrm{N}

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With that push, they have accelerated their masses, which means they have _____ of their bodies.
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