States that when a gas is held at a constant temperature and mass in a closed container, the volume and pressure vary inversely. The equation to use is P1V1=P2V2.
Given
V1=200mL×1L1000mL=0.2 L
P1=700 mmHg
V2=100mL×1L1000mL=0.1 L
Unknown
P2
Equation
P1V1=P2V2
Solution
Rearrange the equation to isolate P2 and solve.
P2=P1V1V2
P2=(700mmHg×0.2L)0.1L=1400 L, which must be rounded to 1000 L because all of the measurements have only one significant figure.
Answer:
The molarity of the solution is 0.048 M (option B)
Explanation:
<u>Step 1: </u>Data given
Sucralfate has a molar mass of 2087 g/mole
mass = 1g
volume = 10 mL
<u>Step 2: </u> Calculate moles of sucralfate
Number of moles = mass of sucralfate / Molar mass of sucralfate
Number of moles = 1 g / 2087 g/mole = 4.79 * 10^-4 moles
<u>Step 3:</u> Calculate molarity
Molarity = Number of moles / volume
Molarity = (4.79 * 10^-4 moles) / (10 *10^-3 L)
Molarity = 0.0479 M ≈ 0.048 M
The molarity of the solution is 0.048 M (option B)
Answer:
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Answer:
the concentration in moles per litre of is
Explanation:
Molarity
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Answer: I think its C or B
Explanation: Hope this was helpful....
