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Zolol [24]
3 years ago
5

Which is the electron configuration for boron? a. 1s22s3b. 1s22s23s1c. 1s12s22p2d. 1s22s22p1?

Chemistry
2 answers:
vodomira [7]3 years ago
6 0

Answer:

the correct answer is D

Explanation:

dybincka [34]3 years ago
4 0

Answer is: D.

Atomic number is the number of protons, which is characteristic of a chemical element: Boron is an element with atomic number 5, which means it has 5 protons and 5 electrons, bcause atom has neutral charge.

Electron configuration of boron: ₅B: 1s² 2s² 2p¹, it has three valence electrons in 2s and 2p orbitals.

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If 1.00 mol of argon is placed in a 0.500-L container at 27.0 degree C , what is the difference between the ideal pressure (as p
ElenaW [278]

Answer:

2.0 atm is the difference between the ideal pressure and  the real pressure.

Explanation:

If 1.00 mole of argon is placed in a 0.500-L container at 27.0 °C

Moles of argon = n = 1.00 mol

Volume of the container,V  = 0.500 L

Ideal pressure of the gas = P

Temperature of the gas,T = 27 °C = 300.15 K[/tex]

Using ideal gas equation:

PV=nRT

P=\frac{1.00 mol\times 0.0821 L atm/mol K\times 300.15 K}{0.500 L}=49.28 atm

Vander wall's of equation of gases:

The real pressure of the gas= p_v

For argon:

a=1.345 L^2 atm/mol^2

b=0.03219 L/mol.

(p_v+(\frac{an^2}{V^2})(V-nb)=nRT

(p_v+(\frac{(1.345 L^2 atm/mol^2)\times (1.00 mol)^2}{(0.500 L)^2})(0.500 L-1.00 mol\times 0.03219L/mol)=1.00 mol\times 0.0821 L atm/mol K\times 300.15 K

p_v = 47.29 atm

Difference :p - p_v= 49.28 atm - 47.29 atm = 1.99 atm\approx 2.0 atm

2.0 atm is the difference between the ideal pressure and  the real pressure.

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