What is the amplitude of a Node?

A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

<u>Answer:</u> The mass of glucose in final solution is 0.420 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

3 years ago

calculate the ph for each case in the titration of 50.0 ml of 0.130 m hclo(aq) with 0.130 m koh(aq). use the ionization constant

-BARSIC- [3]

The ph before the addition of any Koh is<u> 10.105.</u>

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

After the addition of 50 ml KOH,

moles of KOH = 50 * 0.13 =<u> 6.5 mmol </u>

<u>moles </u><u>of HClO = 50 * 0.13 = 6.5 mmol </u>

occurred hydrolysis solution,

pH = 0.5(14 + pKa + log [base conjugate])

pH = 0.5(14 + (- log (4 * 10^-8)) + log (6.5/(50 + 50)))

pH = <u>10.105</u>

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.

The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.

Learn more about concentration here:-brainly.com/question/26255204

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4 0

2 years ago

Metallic bonds form between what kinds of atoms?

valentinak56 [21]

Answer: A metallic bond is a type of chemical bond formed between positively charged atoms in which the free electrons are shared among a lattice of cations. In contrast, covalent and ionic bonds form between two discrete atoms. Metallic bonding is the main type of chemical bond that forms between metal atoms.

Explanation:

NOT MY WORDS! I HOPE THIS HELP!!!!!

3 0

3 years ago

Read 2 more answers

A mixture of H2 and water vapor is present in a closed vessel at 20. 00°C. The total pressure of the system is 755. 0 mmHg. The

MAVERICK [17]

The partial stress of H2 is 737.47 mmHg Let's observe the Ideal Gas Law to find out the whole mols.

We count on that the closed vessel has 1L of volume

P.V=n.R.T
We must convert mmHg to atm. 760 mmHg.
1 atm
755 mmHg (755/760) = 0.993 atm
0.993 m.1L=n.0.082 L.atm/mol.K .
293 K(0.993 atm 1.1L)/(0.082mol.K /L.atm).
293K = n
0.0413mols = n

These are the whole moles. Now we are able to know the moles of water vapor, to discover the molar fraction of it.

P.V=n.R.T
760 mmHg. 1 atm
17.5 mmHg (17.5 mmHg / 760 mmHg)=0.0230 atm
0.0230 m.1L=n.0.082 L.atm/mol.K.293 K(0.0230atm.1L)/(0.082mol.K/L.atm .293K)=n 9.58 × 10 ^ 4 mols = n.
Molar fraction = mols )f gas/general mols.
Molar fraction water vapor =9.58×10^ -four mols / 0.0413 mols
Sum of molar fraction =1
1 - 9.58 × 10 ^ 4 × mols / 0.0413 ×mols = molar fraction H2
0.9767 = molar fraction H2
H2 pressure / Total pressure =molar fraction H2
H2 pressure / 55mmHg = =0.9767 0.9767 = h2 pressure =755 mmHg.
737,47 mmHg.

<h3>What is a mole fraction?</h3>

Mole fraction is a unit of concentration, described to be identical to the variety of moles of an issue divided through the whole variety of moles of a solution. Because it's miles a ratio, mole fraction is a unitless expression.

Thus it is clear that the partial pressure of H2 is 737,47 mmHg.

To learn more about partial pressure refer to the link :

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5 0

3 years ago

A student prepares a aqueous solution of butanoic acid . Calculate the fraction of butanoic acid that is in the dissociated form

ella [17]

Answer:

15.4%

Explanation:

If Ka = 0.54 mM = 1.51x10⁻⁵

Then;

C₄H₈O₂ --------> C₄H₇O₂⁻ + H⁺

I 0.54x10⁻³ 0 0

E 0.54x10⁻³(1-x) 0.54x10⁻³x 0.54x10⁻³x

Recall that x is the percentage degree of dissociation

From the ICE table;

Ka = [C₄H₇O₂⁻] [ H⁺]/[C₄H₈O₂]

1.51x10⁻⁵=(0.54x10⁻³x) (0.54x10⁻³x)/ 0.54x10⁻³(1-x)

1.51x10⁻⁵ = 0.54x10⁻³x^2/1-x

1.51x10⁻⁵(1-x) = 0.54x10⁻³x^2

1.51x10⁻⁵ - 1.51x10⁻⁵x = 0.54x10⁻³x^2

Hence;

0.54x10⁻³x^2 + 1.51x10⁻⁵x - 1.51x10⁻⁵=0

x^2 + 0.028x - 0.028 = 0

Solving the quadratic equation here;

x = 0.154 or −0.182

Ignoring the negative result, x = 0.154

Hence, fraction of butanoic acid that is in the dissociated form in this solution = 15.4%

3 0

3 years ago