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zloy xaker [14]
4 years ago
15

Which element of art creates edges of shapes and visual cues for the viewer in terms of both motion and space?

Physics
2 answers:
mr Goodwill [35]4 years ago
7 0
The element of art that creates edges of shapes and visual cues for the viewer in terms of both motion and space is line. The correct option among all the options that are given in the question is the third option or option "c". The lines have the ability to create a sense of motion when drawn in spaces. 
GaryK [48]4 years ago
5 0
The correct answer for the question that is being presented above is this one: "c. line." The <span>element of art creates edges of shapes and visual cues for the viewer in terms of both motion and space is the line. Line is one of the basic elements of art.</span>
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Explain the purpose of a three-valve manifold in closed tank level measurement installations.
mamaluj [8]

Answer:

A three valve manifold serves to protect the capsule from being exposed to pressures above the acceptable range and also enables transmitter isolation from the loop of the process

In closed tank level measurement installations the pressure of the gas if presence of gas on top of the liquid will need to be taken account by the use of a reference connection from the level transmitter to the tank top. The valve used in pressure equalization is kept close when the process system is operating normally.

In the event that the transmitter is removed or put into service, it is necessary to ensure that the gas phase which is at the higher pressure is does not over-range the Differential Pressure DP capsule

Explanation:

7 0
3 years ago
The electrical resistance of an element in a platinum resistance thermometer at 100°c, 0°c and room temperature are 75.00Ω, 63.0
Dominik [7]

Answer:

16.6 °C

Explanation:

From the question given above, the following data were obtained:

Temperature at upper fixed point (Tᵤ) = 100 °C

Resistance at upper fixed point (Rᵤ) = 75 Ω

Temperature at lower fixed point (Tₗ) = 0 °C

Resistance at lower fixed point (Rₗ) = 63.00Ω

Resistance at room temperature (R) = 64.992 Ω

Room temperature (T) =?

T – Tₗ / Tᵤ – Tₗ = R – Rₗ / Rᵤ – Rₗ

T – 0 / 100 – 0 = 64.992 – 63  / 75 – 63

T / 100 = 1.992 / 12

Cross multiply

T × 12 = 100 × 1.992

T × 12 = 199.2

Divide both side by 12

T = 199.2 / 12

T = 16.6 °C

Thus, the room temperature is 16.6 °C

6 0
3 years ago
The
guapka [62]
The NUCLEUS is the center of the atom. it contains protons and NEUTRONS

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6 0
3 years ago
An object moving due to gravity can be described by the motion equation y=y0+v0t−12gt2, where t is time, y is the height at tha
LenaWriter [7]

Answer:

t=6.4534 s

Explanation:

This is an exercise where you need to use the concepts of <em>free fall objects</em>

Our <u>knowable variables</u> are initial high, initial velocity and the acceleration due to gravity:

y_{0}=75m

v_{oy} =20m/s

g=9.8 m/s^{2}

At the end of the motion, the <u><em>rock hits the ground</em></u> making the final high y=0m

y=y_{o}+v_{oy}*t-\frac{1}{2}gt^{2}

If we <em>evaluate the equation</em>:

0=75m+(20m/s)t-\frac{1}{2}(9.8m/s^{2})t^{2}

This is a classic form of <u><em>Quadratic Formula</em></u>, we can solve it using:

t=\frac{-b ± \sqrt{b^{2}-4ac } }{2a}

a=-4.9\\b=20\\c=75

t=\frac{-(20) + \sqrt{(20)^{2}-4(-4.9)(75) } }{2(-4.9)}=-2.37s

t=\frac{-(20) - \sqrt{(20)^{2}-4(-4.9)(75) } }{2(-4.9)}=6.4534s

Since the <u><em>time can not be negative</em></u>, the <em>reasonable answer</em> is

t=6.4534s

8 0
3 years ago
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