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3 years ago

8. A tank shoots a projectile at an angle of 67* above the horizon and at a speed of 53 m/s

Physics

1 answer:

BlackZzzverrR [31]3 years ago

8 0

Answer:

Explanation:

We are tp calculate the range of the projectile. This is expressed as;

R = 2Usin theta/g

Given

U = 53m/s

Theta = 67°

Substitute;

R = 2(53)sin67/9.8

R = 106sin67/9.8

R = 106(0.9205)/9.8

R = 97.57/9.8

R = 9.96m

Hence the enemy is 9.98m located for a direct hit.

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