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Reil [10]
3 years ago
10

8. A tank shoots a projectile at an angle of 67* above the horizon and at a speed of 53 m/s

Physics
1 answer:
BlackZzzverrR [31]3 years ago
8 0

Answer:

Explanation:

We are tp calculate the range of the projectile. This is expressed as;

R = 2Usin theta/g

Given

U = 53m/s

Theta = 67°

Substitute;

R = 2(53)sin67/9.8

R = 106sin67/9.8

R = 106(0.9205)/9.8

R = 97.57/9.8

R = 9.96m

Hence the enemy is 9.98m located for a direct hit.

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Answer:

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8 0
3 years ago
A 100 Kg man is diving off a 50 meter cliff. What is his kinetic energy when he is 20 meters from the water?
iren2701 [21]

Answer:

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Explanation:

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Generally the equation for Kinetic Energy is is mathematically given by

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K.E=29.403125J

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Answer:

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