8. A tank shoots a projectile at an angle of 67* above the horizon and at a speed of 53 m/s

Physics

1 answer:

BlackZzzverrR [31]2 years ago

8 0

Answer:

Explanation:

We are tp calculate the range of the projectile. This is expressed as;

R = 2Usin theta/g

Given

U = 53m/s

Theta = 67°

Substitute;

R = 2(53)sin67/9.8

R = 106sin67/9.8

R = 106(0.9205)/9.8

R = 97.57/9.8

R = 9.96m

Hence the enemy is 9.98m located for a direct hit.

You might be interested in

Please help with my geology hw

Dominik [7]

Uhhhh not a question the can be answered sorry :/

3 0

2 years ago

why is the earth more attracted to the sun gravitational pull than the gravitational pull of the moon

Ierofanga [76]

First, let's take a look at the equation for the force of gravity between two objects:

F = (GMm)/r², where,

G = gravitational constant = 6.67 x 10⁻¹¹
M = mass of one object
m = mass of the other object
r = distance between the two objects

From this equation, we can see that the force of gravity is directly proportional to the mass of the two objects and inversely proportional to the distance between them. We can then say that the Earth is more attracted to the sun than the moon because of the massive mass of the Sun (1.9891 x 10³⁰) compared to moon (7.3577 x 10²²). Although, the moon is nearer to the Earth, it has little effect to bring down the gravitational pull of the Sun.

5 0

2 years ago

Asexual reproduction involves only one parent. The offspring of this type of reproduction have - F DNA identical to the DNA of t

Sedbober [7]

Answer:

DNA identical to the DNA of the parent

Explanation:

5 0

2 years ago

an 1150kg elevator moving down speeds up at a rate of 3.5m/s. what is the tension in the supporting cables?

gtnhenbr [62]

Answer:

The tension force in the supporting cables is 7245N

Explanation:

There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:

$F_{net} = F_g - F = m\cdot g - F\\$