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natulia [17]
4 years ago
10

A massive tractor rolls down a country road. in a perfectly inelastic collision, a small sports car runs into the machine from b

ehind. (i) which vehicle experiences a change in momentum of larger magnitude
Physics
2 answers:
Helga [31]4 years ago
5 0
The answer for this change in the magnitude of momentum is the same for both because momentum is always conserved so both vehicles have the identical change. 
So for determining who has the greater change in kinetic energy, momentum (P) = mv so P^2 = m^2 v^2 P^2 / 2m = 1/2 m v^2 = energy So the weightier the mass the smaller the energy change for the same momentum change so in here, the car has a greater change in kinetic energy.
Tresset [83]4 years ago
3 0

Answer:

c) Their momentum changes are the same size.

Explanation:

In order to understand this you need to remember that the momentum is divided equally in the collision, so the correct answer to this is the fact that their momentum will changes the same, because that is how energy is preserved, the thing that could be different is that they are affected different by that momentum, it would probably affect differently the small car and the tractor, it would probably have a lot of impact for the small car.

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Answer:

B = 8.0487mT

Explanation:

To solve the exercise it is necessary to take into account the considerations of the Magnetic Force described by Faraday,

The magnetic force is given by the formula

F =BILsin\theta

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B = Magnetic Field

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According to our data we have that

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As we know our equation must be modificated to Force per length unit, that is

\frac{F}{L} = BI sin(90)

Replacing the values we have that

0.132 = 16.4 (1) B

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8 0
4 years ago
Why is everything spinning? Moons, planets and stars all rotate on their axes, moons orbit planets, planets orbit stars, spiral
kow [346]

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Conservation of angular momentum

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4 years ago
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Answer:

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3 years ago
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Answer:

W = 1.432 KJ

Explanation:

given,

mass = 22.2 Kg

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Work done = ?

W = F d cosθ

a = 0 because it is moving with constant speed

equating all the forces acting  in x direction

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equating all the forces acting  in y direction

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now,

N = mg - F sinθ

putting value of N

F cosθ = μ mg -μ F sinθ

F (cosθ + μsinθ ) = μ mg

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F =67.28 N

now,

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