) each plate of a parallel-plate air-filled capacitor has an area of 0.0020 , and the separation of the plates is an electric fi
eld of is present between the plates. what is the surface charge density on the plates? (ε0 = 8.85 × 10-12 c2/n • m2)
1 answer:
I attached the full question.
We know that for a parallel-plate capacitor the surface charge density is given by the following formula:
Where V is the voltage between the plates and d is separation.
Voltage is by definition:
Voltage is analog to the mechanical work done by the force.
Above formula is correct only If the field is constant, and we can assume that it is since no function has been given.
The charge density would then be:
Please note that elecric permittivity of air is very close to elecric permittivity of vacum, it is common to use them <span>interchangeably</span>.
We know that for a parallel-plate capacitor the surface charge density is given by the following formula:
Where V is the voltage between the plates and d is separation.
Voltage is by definition:
Voltage is analog to the mechanical work done by the force.
Above formula is correct only If the field is constant, and we can assume that it is since no function has been given.
The charge density would then be:
Please note that elecric permittivity of air is very close to elecric permittivity of vacum, it is common to use them <span>interchangeably</span>.
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Answer:
Part a)
%
Part b)
%
Explanation:
As we know that total power used in the room is given as
here we have
Part a)
Since power supply is at 110 Volt so the current obtained from this supply is given as
now resistance of transmission line
now power loss in line is given as
Now percentage loss is given as
%
Part b)
now same power must have been supplied from the supply station at 110 kV, so we have
now power loss in line is given as
Now percentage loss is given as
%