Answer:
<u>1092K</u>
Explanation:
We can use the combined gas law to answer this question:
P1V1/T1 = P2V2/T2,
where P, V and T are the Pressure, Volume, and Temperature for initial (1) and Final (2) conditions. Temperatures must be in Kelvin.
The problem states that V2 = 2V1 and P2 = 2P1.
Let's rearrange to solve for T2, which is the question:
T2 = T1(P2/P1)(V2/V1)
Note how the pressure and temperature values are written: as ratios. Enter the values:
T2 = (273K)(P2/P1)(V2/V1)
T2 = (273K)(2P1/P1)(2V1/V1) [Use the expressions for V2 and P2 from above]
T2 = (273K)(2)(2)
T2 = 1092K
Answer : The oxidation state of Mg in Mg(s) is (0).
Explanation :
Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.
Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.
Rules for Oxidation Numbers are :
The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
The given chemical reaction is:
![Mg(s)+2H_2O(l)\rightarrow Mg(OH)_2(s)+H_2(g)](https://tex.z-dn.net/?f=Mg%28s%29%2B2H_2O%28l%29%5Crightarrow%20Mg%28OH%29_2%28s%29%2BH_2%28g%29)
In the given reaction, the oxidation state of Mg in Mg(s) is (0) because it is a free element and the oxidation state of Mg in
is (+2).
Hence, the oxidation state of Mg in Mg(s) is (0).
Antimony also forms trihalides and pentahalides, such as SbF3 , where its oxidation state is +3, and SbF5 , where its oxidation state is +5
Answer:
K2CO3 = K2O + CO2
Explanation:
In a chemical equation, the number of atoms on the left needs to be balanced with the number of atoms on the right, and there has to be the same number of the same *type* of atom on both sides as well.
On the left:
2 K
1 C
3 O
and on the right,
2 K
1 O
On the right, there are a few atoms missing, specifically, 1 C and 2 O.
The missing atoms then should be added to the side missing the atoms, preferably in a stable molecule. Luckily, CO2 contains exactly 1 C, and 2 O s, and is quite stable. So, a "CO2" has to be added on the left
Answer:
2.7g/cm³
Aluminum
Explanation:
Given parameters:
Mass of the cube = 72.9g
Unknown:
Density of the cube = ?
Solution:
To solve this problem, we need to find the density of the cube. The mass is given and the dimensions of the solid figure.
Now;
Density is the mass per unit volume of a substance
Density =
Volume of the cube = L³ = 3³ = 27cm³
So;
Density =
= 2.7g/cm³
The body is aluminum because it has a density of 2.7g/cm³