Answer:
n=0.03928 moles
Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles
Explanation:
The amount of oxygen which lung can have is 20% of 5 L which is the capacity of lungs
Volume of oxygen in lungs =V=5*20%= 1 L=
Temperature=T=
Pressure at sea level = P= 1 atm=
R is universal Gas Constant =8.314 J/mol.K
Formula:

Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles
Answer:
Normal Force, Applied force, Gravitational Force, Spring Force
Explanation:
Normal Force so that he does not fall into trampoline, spring because the trampoline spring down when the force goes down, then up putting force upwards, gravitation because of gravity, and applied because of jumping
Answer:
False
Explanation:
Higher frequency signals have shorter wavelengths. Hence, the 64 GHz signal will have a shorter wavelength than the 57 GHz signal.
Frequency and wavelength are inversely proportional meaning as frequency increases wavelength decreases and as frequency decreases wavelength increases.
Cheers.
Answer:
<em>A. 751 ohm</em>
Explanation:
Impedance: <em>This is the total opposition to the flow of current in an a.c circuit by any or all of the three circuit elements ( R, L, C). The unit of impedance is Ohms (Ω). The impedance in a parallel circuit is gives a s</em>
<em>Z = RXₐ/√(Xₐ² + R²)............................... Equation 1</em>
<em>Where Z = The impedance of the a.c circuit, Xₐ = capacitive reactance, R = resistance.</em>
<em>Given: Xₐ = 962 Ω, R = 1200 Ω</em>
<em>Substituting these values into equation 1,</em>
<em>Z = 962×1200/√(962² + 1200²)</em>
<em>Z = 1154400/√(925444 + 1440000)</em>
<em>Z = 1154400/√(925444+1440000</em>
<em>Z = 1154400/1538</em>
<em>Z = 750.59 Ω</em>
<em>Z≈ 751 Ω</em>
<em>Therefore the impedance of the circuit = 751 Ω</em>
<em>The right option is A. 751 ohm</em>
Answer:
c
Explanation:
<u>impulse</u><u> </u><u>Is</u><u> </u><u>the </u><u>product</u><u> </u><u>of </u><u>force </u><u>and </u><u>distance</u><u> </u><u>so </u><u>it's </u><u>generally</u><u> </u><u>formula</u><u> </u>