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Alla [95]
3 years ago
15

A 150 mL sample of hydrochloric acid (HCl) completely reacted with 60.0 mL of a 0.100 M NaOH solution. The equation for the reac

tion is given below.
HCl + NaOH mc011-1.jpg NaCl + H2O

What was the original concentration of the HCl solution?
Chemistry
2 answers:
Marizza181 [45]3 years ago
7 0
The balanced chemical reaction is expressed as:
HCl + NaOH ---> NaCl + H2O
We are given the amount and the concentration of the sodium hydroxide reactant. This will be the starting point for the calculations. 
0.100 mol NaOH/L solution (0.06 L solution) ( 1 mol HCl / 1 mol NaOH) = 0.006 mol HCl
Molarity = amount in moles / Volume of solution = 0.006 mol HCl/ 0.150 LMolarity = 0.04 M
IceJOKER [234]3 years ago
6 0

Answer : The original concentration of HCl is 0.04 M

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of NaOH solution = 0.100 M

V_1 = volume of NaOH solution = 60.0 ml

M_2 = molarity of HCl solution = ?

V_2 = volume of HCl solution = 150 ml

Now put all the given values in the above law, we get the molarity of HCl solution.

(0.100M)\times 60ml=(M_2)\times (150ml)

M_2=0.04M

Therefore, the original concentration of HCl is 0.04 M

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