The ans is A. 355 m/s as temperature is above stp
Approx. 983274984065823796374 meters away
Answer:
132 N
Explanation:
Given that a 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail
From Newton 2nd law of motion,
Change in momentum = impulse.
Change in momentum = m( V - U )
Substitute all the parameters into the formula
Change in momentum = 1.1 ( 4.5 - 1.5 )
Change in momentum = 1.1 × 3
Change in momentum = 3.3 kgm/s
Impulse = Ft
That is,
Ft = 3.3
Substitute time t into the formula above
F × 0.025 = 3.3
F = 3.3 / 0.025
F = 132 N
Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.
Calculate the minimum speed record at the point B in order for the real question to reach the top
The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.
<h3>How to calculate the final velocity a moving object?</h3>
From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.
It is expressed as;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
- Initial velocity u = 6m/s
- Acceleration a = 85m/s²
- Elapsed time t = 5s
- Final velocity v = ?
Plug the given values into the first equation of motion and solve for v.
v = u + at
v = 6m/s + ( 85m/s² × 5s )
v = 6m/s + 425ms/s²
v = 6m/s + 425m/s
v = 431m/s
The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.
Learn more about the first equation of equation here: brainly.com/question/20381052
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