An Otto cycle engine is analyzed using the cold air standard method. Given the conditions at state 1, compression ratio (r), and
pressure ratio (rp). The specific heats for air are Cp = 1.0045 kJ/kg-K and Cv = 0.7175 kJ/kg-K.
T1 = 300K
P1 = 100 kPa
r = 10
rp = 1.65
a) Determine the temperature (K) at state 2.
b) Determine the pressure (kPa) at state 2.
c) Determine the pressure (kPa) at state 3.
d) Determine the temperature (K) at state 3.
e) Determine the temperature (K) at state 4.
f) Determine the pressure (kPa) at state 4.
g) Determine the net work output (kJ/kg/cycle) for the engine.
h) Determine the heat addition (kJ/kg/cycle) for the engine.
i) Determine the efficiency (%) of the engine.
Points will be given to answer showing all the work done to get right answer.
T1 = 300K
P1 = 100 kPa
r = 10
rp = 1.65
a) Determine the temperature (K) at state 2.
b) Determine the pressure (kPa) at state 2.
c) Determine the pressure (kPa) at state 3.
d) Determine the temperature (K) at state 3.
e) Determine the temperature (K) at state 4.
f) Determine the pressure (kPa) at state 4.
g) Determine the net work output (kJ/kg/cycle) for the engine.
h) Determine the heat addition (kJ/kg/cycle) for the engine.
i) Determine the efficiency (%) of the engine.
Points will be given to answer showing all the work done to get right answer.
1 answer:
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Answer with Explanation:
The capillary rise in 2 parallel plates immersed in a liquid is given by the formula
where
is the surface tension of the liquid
is the contact angle of the liquid
is density of liquid
'g' is acceleratioj due to gravity
'd' is seperation between thje plates
Part a) When the liquid is water:
For water and glass we have
Applying the values we get
Part b) When the liquid is mercury:
For mercury and glass we have
Applying the values we get
The negative sign indicates that there is depression in mercury in the tube.