Answer:
σ = 391.2 MPa
Explanation:
The relation between true stress and true strain is given as:
σ = k εⁿ
where,
σ = true stress = 365 MPa
k = constant
ε = true strain = Change in Length/Original Length
ε = (61.8 - 54.8)/54.8 = 0.128
n = strain hardening exponent = 0.2
Therefore,
365 MPa = K (0.128)^0.2
K = 365 MPa/(0.128)^0.2
k = 550.62 MPa
Now, we have the following data:
σ = true stress = ?
k = constant = 550.62 MPa
ε = true strain = Change in Length/Original Length
ε = (64.7 - 54.8)/54.8 = 0.181
n = strain hardening exponent = 0.2
Therefore,
σ = (550.62 MPa)(0.181)^0.2
<u>σ = 391.2 MPa</u>
Answer:
when 5% excess air is supplied, moles of air supplied/moles of fuel = 
Explanation:
Equivalence ratio = 0.6
Equivalence ratio = Actual air to fuel ratio (AAFR)/ stoichiometric air to fuel ratio SAFR
combustion reaction of propane is
From above reaction, 1 mole of propane, from the reaction, 5 moles of oxygen required,
we know that air contains 21% O_2 and 79% N_2,
Therefore, moles of air based on stoichiometry 
Theoretical air to fuel ratio 
Given
Actual Air Fuel Ratio 
when 5% excess air is supplied, moles of air supplied/moles of fuel =
Answer:
I think that plane's name is
KLM ....Because you can see the mysterious Leter in the plane's
Forward and the back of the plane
Answer:
- #include <iostream>
- using namespace std;
- void printLarger(int a, int b){
-
- if(a > b){
- cout<<a;
- }else{
- cout<<b;
- }
- }
- int main()
- {
- printLarger(4, 5);
- return 0;
- }
Explanation:
The solution code is written in C++.
Firstly define a function printLarger that has two parameters, a and b with both of them are integer type (Line 5). In the function, create an if condition to check if a bigger than b, print a to terminal (Line 7-8). Otherwise print b (Line 9-10).
In the main program, test the function by passing 4 and 5 as arguments (Line 16) and we shall get 5 printed.
