To develop the problem it is necessary to apply the kinematic equations for the description of the position, speed and acceleration.
In turn, we will resort to the application of Newton's second law.
PART A) For the first part we look for the time, in a constant acceleration, knowing the speeds and the displacement therefore we know that,
![X_f = X_i +\frac{1}{2}(V_i+V_f)t](https://tex.z-dn.net/?f=X_f%20%3D%20X_i%20%2B%5Cfrac%7B1%7D%7B2%7D%28V_i%2BV_f%29t)
Where,
X = Desplazamiento
V = Velocity
t = Time
In this case there is no initial displacement or initial velocity, therefore
![X_f = \frac{1}{2} (V_i+V_f)t](https://tex.z-dn.net/?f=X_f%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%28V_i%2BV_f%29t)
Clearing for time,
![t = \frac{2X_f}{(V_i+V_f)}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B2X_f%7D%7B%28V_i%2BV_f%29%7D)
![t = \frac{2*1.2}{24+0}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B2%2A1.2%7D%7B24%2B0%7D)
![t = 0.1s](https://tex.z-dn.net/?f=t%20%3D%200.1s)
PART B) This is a question about the impulse of bodies, where we turn to Newton's second law, because:
F = ma
Where,
m=mass
a = acceleration
Acceleration can also be written as,
![a= \frac{\Delta V}{t}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7B%5CDelta%20V%7D%7Bt%7D)
Then
![F = m\frac{\Delta V}{t}](https://tex.z-dn.net/?f=F%20%3D%20m%5Cfrac%7B%5CDelta%20V%7D%7Bt%7D)
![F = m\frac{V_f-V_i}{t}](https://tex.z-dn.net/?f=F%20%3D%20m%5Cfrac%7BV_f-V_i%7D%7Bt%7D)
![F = m\frac{-V_i}{t}](https://tex.z-dn.net/?f=F%20%3D%20m%5Cfrac%7B-V_i%7D%7Bt%7D)
![F = \frac{(1600kg)(-24m/s)}{(0.1s)}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B%281600kg%29%28-24m%2Fs%29%7D%7B%280.1s%29%7D)
![F = -384000N](https://tex.z-dn.net/?f=F%20%3D%20-384000N)
Negative symbol is because the force is opposite of the direction of moton.
PART C) Acceleration through kinematics equation is defined as
![V_f^2=V_i^2-2ax](https://tex.z-dn.net/?f=V_f%5E2%3DV_i%5E2-2ax)
![0 = (24m/s)^2-2*a(1.2m)](https://tex.z-dn.net/?f=0%20%3D%20%2824m%2Fs%29%5E2-2%2Aa%281.2m%29)
![a = \frac{(24m/s)^2}{1.2m}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%2824m%2Fs%29%5E2%7D%7B1.2m%7D)
![a=480m/s^2](https://tex.z-dn.net/?f=a%3D480m%2Fs%5E2)
The gravity is equal to 0.8, then the acceleration is
![a = 480*\frac{g}{9.8}](https://tex.z-dn.net/?f=a%20%3D%20480%2A%5Cfrac%7Bg%7D%7B9.8%7D)
![a = 53.3g](https://tex.z-dn.net/?f=a%20%3D%2053.3g)
The process by which an unstable atomic nucleus loses energy by radiation
Answer:
B
Explanation:
You lose more calories, and are on a lower risk
Changing the proportions of substances in an alloy will change the physical properties of that alloy. The differing substances will change the metallic structure of the crystals of the metal alloy, and this alters the ductility, durability, hardness, tensile strength, toughness and other characteristics we assess are regards alloys.
Explanation:
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