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Elodia [21]
2 years ago
15

To which group of the periodic table do lithium and potassium belong?

Chemistry
2 answers:
Korolek [52]2 years ago
7 0

Answer: 1=alkali metals

2= 1g/mL

3= Mercury

Explanation:

1=The alkali metals are six chemical elements in Group 1, the leftmost column in the periodic table. They are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).

2=It's no coincidence that water has a density of 1. Density is mass divided by volume (ρ=m/v), and water was used as the basis for establishing the metric unit of mass, which means a cubic centimeter (1cm3) of water weighs one gram (1g).

So, 1g/1cm3 = 1 g/cm3, giving water its easy-to-remember density. However, water's exact density depends on both the air pressure and the temperature of the area. These variations in density are very slight though, so unless you need to know very exact calculations or the experiment takes place in an area with an extreme temperature/pressure, you can continue to use 1 g/cm3 for water density. You can look at the chart in the next section to see how water's density changes with temperature.

3=There are two elements that are liquid in room temperature.

Bromine (Br) melts at 265.9 K

Mercury (Hg) melts at 234.32 K - This is very interesting because all of Mercury's neighboring elements are solids at room temperature. Mercury is also much less reactive than Cadmium and Zinc which are directly above Mercury. Mercury doesn't conduct heat or electricity as well as other members of its group. Most metals are solids at room temperature because they share their valence electrons with surrounding metal atoms. However Mercury hangs onto its 6 valence electrons tighter than any other atom. Thus Mercury-Mercury bonds are weaker compared to other metal-metal bonds. It is also the only metal that doesn't form diatomic molecules in the gas phase. Since the amount of heat required to overcome the weak Mercury-Mercury bonds is lower, Mercury melts and boils at very low temperatures.

s344n2d4d5 [400]2 years ago
6 0

Answer:

1)alkali metals

2)1g/ml

3) mercury

Explanation:

<em><u>HEY!</u></em><em><u>!</u></em><em><u>^</u></em><em><u>^</u></em>

<em><u>have </u></em><em><u>a </u></em><em><u>good </u></em><em><u>day</u></em>

<em><u>thank </u></em><em><u>me </u></em><em><u>later</u></em>

<em><u>carryonlearing </u></em>

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Which of the following is not a common use of gypsum? a. wallboard/drywall for homes b. a primary ingredient for toothpaste c. s
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How many moles are in 17.2g k2s
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3 0
3 years ago
N2+3H2 → 2NH3
s2008m [1.1K]

Explanation:

N2 (g) + H2 (g) gives out NH3 (g)

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.(If you balance the hydrogen reactant with a whole number first, I can guarantee you that you will have to give NH3 a new stoichiometric coefficient.)

N2 (g) + 3H2 (g) gives out 2NH3 (g)

The stoichiometric coefficients tell you that if we can somehow treat every component in the reaction as the same (like on a per-mol basis, hinthint), then one "[molar] equivalent" of nitrogen yields two [molar] equivalents of ammonia.

Luckily, one mol of anything is equal in quantity to one mol of anything else because the comparison is made in the units of mols.

So what do we do? Convert to

mols (remember the hint?).

28g N2 × 1 mol N2/ 2 × 14.007) g N2

= 0.9995 mol N2

At this point you don't even need to calculate the number of mols of H2 . Why? Because H2 is about 2 g/mol, which means we have over 10 mols of H2. We have 1 mol N2, and we need three times as many mols of H2 as we have

N2.

After doing the actual calculation you should realize that we have about 4 times as much H2 as we need. Therefore the limiting reagent is clearly N2.

Thus, we should yield 2×0.9995=1.9990 mols of NH3 (refer back to the reaction). So this is the second and last calculation we need to do:

1.9990 mol NH3 × 17.0307 g NH3/ 1 mol NH3

= 34.0444 g NH3

Hope it helpz~

4 0
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