Write equations for the following: (b) an addition reactionbetween cyclohexene and Cl₂;

Chemistry

1 answer:

lorasvet [3.4K]2 years ago

7 0

The required equation for an addition reaction between cyclohexene and Cl2 .

Cyclohexene + Cl2 → 1,2-dichlorocyclohexane

What is addition reaction ?

it is type of reaction in which one molecule combines with another molecule to form larger molecules .

addition reaction types are electrophilic , nucleophilic and free radical addition reaction .

<h3>What is free radical addition reaction ?</h3>

it is type of addition reaction where functional group is added to a compound through a free radical intermediate .

The free radical addition reaction involves chain initiation , chain propagation and chain termination .

Learn more about addition reaction here :

brainly.com/question/23960104

#SPJ4

You might be interested in

Write balanced molecular equation for the reaction between nitric acid and calcium hydroxide. Express your answer as a chemical

eimsori [14]

<u>Answer:</u> The balanced chemical equation for the reaction of nitric acid and calcium hydroxide is written below.

<u>Explanation:</u>

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the reaction of nitric acid and calcium hydroxide follows:

$2HNO_3(aq.)+Ca(OH)_2(aq.)\rightarrow Ca(NO_3)_2(aq.)+2H_2O(l)$

By Stoichiometry of the reaction:

2 moles of nitric acid reacts with 1 mole of calcium hydroxide to produce 1 mole of calcium nitrate and 2 moles of water molecule.

Hence, the balanced chemical equation for the reaction of nitric acid and calcium hydroxide is written below.

6 0

4 years ago

What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon

Varvara68 [4.7K]

Answer: 31.8 g

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Al_2O_3=\frac{60.0g}{102g/mol}=0.59moles$

$\text{Moles of} C=\frac{30.0g}{12g/mol}=2.5moles$

$Al_2O_3+3C\rightarrow 2Al+3CO$

According to stoichiometry :

1 mole of $Al_2O_3$ require 3 moles of $C$

Thus 0.59 moles of $Al_2O_3$ will require= $\frac{3}{1}\times 0.59=1.77moles$ of $C$

Thus $Al_2O_3$ is the limiting reagent as it limits the formation of product and $C$ is the excess reagent as it is present in more amount than required.

As 1 mole of $Al_2O_3$ give = 2 moles of $Al$