Answer:
it is the same way it is purified in the state
Answer:
False.
Explanation:
The given statement is false because for hot vacuum filtration, the filter paper should be wet rather than dry when pouring the hot solution into the Buchner funnel. This is because The possible explanation the filter paper needs to be wetted is not only to allow it to adhere to the funnel, but also to promote the solute to filter down readily across its pores of the paper without wetting it (this is true for organic and aqueous solvents).
The name of the acid is Bromous acid and the Formula of the acid is HBrO₂.
<h3>What is Acids ? </h3>
Acids is defined as substances that is able to donate a proton or hydrogen ion to other substance. Acids acts as proton donor.
<h3>What is Oxoacids ? </h3>
An oxoacids is an acids that contains oxygen. It is also called oxyacids or ternary acids. Oxoacids are the acids of oxoanions.
If anion name contains the suffix ‘ate’ then replace ‘ate’ with ‘ic’.
If anion name contains the suffix ‘ite’ then replace ‘ite’ with ‘ous’.
Given anion is bromite. Formula of bromite is BrO₂⁻. It is an oxoanion.
Now write the name of acid. Here anion name contains the suffix ite so replace the ‘ite’ of bromite with ‘ous’.
The name of the acid is Bromous acid.
Formula of the acid is HBrO₂.
Thus from the above conclusion we can say that The name of the acid is Bromous acid and the Formula of the acid is HBrO₂.
Learn more about Oxoacids here: brainly.com/question/21795128
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Answer:
V₂ = 12.5 mL
Explanation:
Given data:
Initial volume = 100.0 mL
Initial pressure = 50.0 KPa
Final volume = ?
Final pressure = 400.0 KPa
Solution:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
50.0 KPa × 100.0 mL = 400 KPa × V₂
V₂ = 5000 KPa.mL/ 400 KPa
V₂ = 12.5 mL
