Answer:
The Lewis structure to this question can be described as follows:
Explanation:
Structure of Lewis for
:
The maximum number of electrons from valence in
is 8 (6 from S as well as 2 from negative change).
The valence electrons in the Lewis structure are placed on four sides of the atom.
Thus the structure of Lewis for
is as follows:
![\left[\begin{array}{ccc} &. .&\\: &S&:\\&. .&\end{array}\right] ^{2-}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%26.%20.%26%5C%5C%3A%20%26S%26%3A%5C%5C%26.%20.%26%5Cend%7Barray%7D%5Cright%5D%20%5E%7B2-%7D)
Lewis Mg Structure:
Complete valence electrons are 2 in Mg.
The Lewis structure for Mg, therefore, is as follows:

The Lewis structure for 
The maximum valence of electrons
in is= 0.
Thus, the structure for
is as follows:

Lewis structure for P :
The maximum number of valence electrons in P is = 5.
Thus, the structure for P is=
