Answer:
b. primitive cubic < body-centered cubic < face-centered cubic
Explanation:
The coordination number is defined as <em>the number of atoms (or ions) surrounding an atom (or ion) in a crystal lattice</em>. Its value gives us a measure of how tightly the spheres are packed together. The larger the coordination number, the closer the spheres are to each other.
- In the <u>primitive cubic</u>, each sphere is in contact with 6 spheres, so its <u>coordination number is 6</u>.
- In the <u>body-centered cubic</u>, each sphere is in contact with 8 spheres, so its <u>coordination number is 12</u>.
- In the <u>face-centered cubic</u>, each sphere is in contact with 12 spheres, so its <u>coordination number is 12</u>.
Therefore, the increasing order in density is the primitive cubic first, then the body-centered cubic, and finally the face-centered cubic.
Answer:
2.5 mol/L
Explanation:
We'll begin by calculating the number of mole in 7 g of KOH. This can be obtained as follow:
Mass of KOH = 7 g
Molar mass of KOH = 39 + 16 + 1
= 56 g/mol
Mole of KOH =?
Mole = mass /molar mass
Mole of KOH = 7 / 56
Mole of KOH = 0.125 mole
Next, we shall convert 50 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
50 mL = 50 mL × 1 L / 1000 mL
50 mL = 0.05 L
Finally, we shall determine the molarity of the KOH solution. This can be obtained as follow:
Mole of KOH = 0.125 mole
Volume = 0.05 L
Molarity of KOH =?
Molarity = mole / Volume
Molarity of KOH = 0.125 / 0.05
Molarity of KOH = 2.5 mol/L
Thus, the molarity of the KOH solution is 2.5 mol/L
The answer I’m sure it’s c
Answer:
Therefore, 107 ml of 2.5% w/v chlorpromazine hydrochloride injection and 393 ml of 0.9% w/v sodium chloride injection are needed to prepare 500 mL of a 0.3% w/v chlorpromazine hydrochloride injection
Explanation:
The method to be used in determining the proportions of each component to be used to get the desired mixture is known as alligation alternate.
Alligation alternate is a method by which to calculate the number of parts of two or more components of a given strength when they are to be mixed to a desired strength. The difference between the strength of the stronger component and the desired strength indicates the number of parts of the weaker component to be used and the difference between the desired strength and the strength of the weaker component indicates the number of parts of the stronger to be used.
Desired strength = 0.3%
Number of parts of 2.5% w/v chlorpromazine hydrochloride injection to be used = 0.9 - 0.3 = 0.6 parts
Number of parts of 0.9% w/v sodium chloride injection to be used = 2.5 - 0.3 = 2.2 parts
Total parts = 2.8 parts
2.8 parts of 0.3% w/v chlorpromazine hydrochloride injection = 500 ml
0.6 parts of 2.5% w/v chlorpromazine hydrochloride injection = 0.6 * 500 ml/2.8 = 107 ml of 2.5% w/v chlorpromazine hydrochloride injection
2.2 parts of 0.9% w/v sodium chloride injection = 2.2 * 500 / 2.8 = 393 ml of 0.9% w/v sodium chloride injection
Therefore, 107 ml of 2.5% w/v chlorpromazine hydrochloride injection and 393 ml of 0.9% w/v sodium chloride injection are needed to prepare 500 mL of a 0.3% w/v chlorpromazine hydrochloride injection