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12345 [234]
3 years ago
8

I will give brainliest! I have an assignment about career exploration. I have to create a 5 minute news segment on why the schoo

l should not get rid of chemistry class. A question I have to include is, "What opportunities can a chemist, chemical engineer, or molecular biologist able to take advantage of as a result of their background in chemistry?"
Chemistry
1 answer:
andriy [413]3 years ago
5 0

Answer:

There are many opportunities a chemist, chemical engineer, and molecular biologist may have. These professions and or practices could become Product Development Scientists, a Clinical Pharmacist, a Biochemist, or a Pharmaceutical Administer. These careers are very important, because people with professions in these areas will be able to get well paying jobs that will most likely have increasing value over time.

Schools need to offer chemistry so people seeking jobs in these areas will be able to do what they love, and for those who are seeking other science related professions like becoming nurses and other important members in the work force, will be able to get the education they need. Chemistry is a college level class, and is a college credit. If you're not seeking a higher profession in the scientific area, you can take it to get a required credit out of the way.

There are a plethora of science jobs out there that are crucial to the wellbeing of people, and these jobs will ALWAYS be important.

This isn't five minutes... but I hope this helps a little. Add a lil' bit more, and you should be good. I really hope this helped.

You might be interested in
What are the possible values of n and ml for an electron in a 5d orbital?
liberstina [14]

Answer:

The answer to your question is n = 5, l = 2, m can be -2, -1, 0, 1 or 2

Explanation:

Data

orbital = 5d

values of n, l, m

Process

1.- Determine the value of n

n is the coefficient of the orbital, in this problem n = 5

2.- Determine the value of l

l takes values depending in the sublevel of energy,

if the sublevel is s  then l = 0

                           p          l = 1

                           d          l = 2

                           f           l = 3

For this problem l = 2

3.- Determine the value of m

when l = 2, m takes values of -2, - 1, 0, 1 or 2

3 0
3 years ago
HELP I DON'T HAVE LONG LEFT AND I'M STRUGGLING SO BAD PLEASE I BEG U TO HELP
vivado [14]
I think it’s oxygen and carbon
8 0
2 years ago
An ideal gas has a volume of 5.00L under a pressure of 1.00 atm and a temperature of 10.0 K. If the temperature is changed to 10
tigry1 [53]

Answer:

6.25 L

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

7 0
3 years ago
Use the periodic table to identify the chemical symbol or name for each element below.
Tom [10]

Answer:yes

Explanation:yeaa

4 0
3 years ago
Read 2 more answers
How many grams are in 3.14 moles of PI₃?
OverLord2011 [107]

Answer:

\boxed {\boxed {\sf 1290 \ g \ PI_3}}

Explanation:

We want to convert from moles to grams, so we must use the molar mass.

<h3>1. Molar Mass</h3>

The molar mass is the mass of 1 mole of a substance. It is the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We are given the compound PI₃ or phosphorus triiodide. Look up the molar masses of the individual elements.

  • Phosphorus (P): 30.973762 g/mol
  • Iodine (I): 126.9045 g/mol

Note that there is a subscript of 3 after the I in the formula. This means there are 3 moles of iodine in 1 mole of the compound PI₃. We should multiply iodine's molar mass by 3, then add phosphorus's molar mass.

  • I₃: 126.9045 * 3=380.7135 g/mol
  • PI₃: 30.973762 + 380.7135 = 411.687262 g/mol

<h3>2. Convert Moles to Grams</h3>

Use the molar mass as a ratio.

\frac {411.687262 \ g \ PI_3}{ 1 \  mol \ PI_3}

We want to convert 3.14 moles to grams, so we multiply by that value.

3.14 \ mol \ PI_3 *\frac {411.687262 \ g \ PI_3}{ 1 \  mol \ PI_3}

The units of moles of PI₃ cancel.

3.14 *\frac {411.687262 \ g \ PI_3}{ 1 }

1292.698 \ g\ PI_3

<h3>3. Round</h3>

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the tens place.

  • 1292.698

The 2 in the ones place tells us to leave the 9.

1290 \ g \ PI_3

3.14 moles of phosphorous triiodide is approximately equal to <u>1290 grams of phosphorus triodide.</u>

4 0
2 years ago
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