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12345 [234]
3 years ago
8

I will give brainliest! I have an assignment about career exploration. I have to create a 5 minute news segment on why the schoo

l should not get rid of chemistry class. A question I have to include is, "What opportunities can a chemist, chemical engineer, or molecular biologist able to take advantage of as a result of their background in chemistry?"
Chemistry
1 answer:
andriy [413]3 years ago
5 0

Answer:

There are many opportunities a chemist, chemical engineer, and molecular biologist may have. These professions and or practices could become Product Development Scientists, a Clinical Pharmacist, a Biochemist, or a Pharmaceutical Administer. These careers are very important, because people with professions in these areas will be able to get well paying jobs that will most likely have increasing value over time.

Schools need to offer chemistry so people seeking jobs in these areas will be able to do what they love, and for those who are seeking other science related professions like becoming nurses and other important members in the work force, will be able to get the education they need. Chemistry is a college level class, and is a college credit. If you're not seeking a higher profession in the scientific area, you can take it to get a required credit out of the way.

There are a plethora of science jobs out there that are crucial to the wellbeing of people, and these jobs will ALWAYS be important.

This isn't five minutes... but I hope this helps a little. Add a lil' bit more, and you should be good. I really hope this helped.

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3 years ago
Which isotope will spontaneously decay and emit particles with a charge of +2?
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Answer: The correct option is 4.

Explanation: All the options will undergo some type of radioactive decay processes. There are 3 decay processes:

1) Alpha decay: It is a decay process in which alpha particle is released which has has a mass number of 4 and a charge of +2.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

2) Beta-minus decay: It is a decay in which a beta particle is released. The  beta particle released has a mass number of 0 and a charge of (-1).

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.

_Z^A\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0\beta

For the given options:

Option 1: This nuclei will undergo beta-plus decay process to form _{25}^{53}\textrm{Mn}

_{26}^{53}\textrm{Fe}\rightarrow _{25}^{53}\textrm{Mn}+_{+1}^0\beta

Option 2: This nuclei will undergo beta-minus decay process to form _{80}^{198}\textrm{Hg}

_{79}^{198}\textrm{Au}\rightarrow _{80}^{198}\textrm{Hg}+_{-1}^0\beta

Option 3: This nuclei will undergo a beta minus decay process to form _{56}^{137}\textrm{Ba}

_{55}^{137}\textrm{Cs}\rightarrow _{56}^{137}\textrm{Ba}+_{-1}^0\beta

Option 4: This nuclei will undergo an alpha decay process to form _{85}^{216}\textrm{At}

_{87}^{220}\textrm{Fr}\rightarrow _{85}^{216}\textrm{At}+_2^4\alpha

Hence, the correct option is 4.

7 0
4 years ago
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Acetals are geminal-diether derivatives of aldehydes or ketones, formed by reaction with two equivalents (or an excess amount) of an alcohol and elimination of water. Ketone derivatives of this kind were once called ketals, but modern usage has dropped that term.

To achieve effective hemiacetal or acetal formation, two additional features must be implemented. First, an acid catalyst must be used because alcohol is a weak nucleophile and second the water produced with the acetal must be removed from the reaction.

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4 years ago
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As a change of state takes place, heat and temperature
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