Answer:
1. Diazonium salt
2. Coupling component
Explanation:
Azo dyes re synthesized by the combination of two organic compounds viz
1. Diazonium salt
2. Coupling component
1) For methyl red, the diazonium salt which is an intermediate product is produced by the reaction of hydrochloric acid (HCL) with anthranilic acid and sodium nitrate (NaNO₂)
2) The produced diazonium salt is then combined with dimethylaniline which is a coupling component rich in electrons to undergo a chemical reaction that by an aromatic substitution mechanism to produce methyl red as the final product.
The correct answer choice from the statement above about investigated factors from lab results is :
Students who spend less time studying after school get lower math grade
Option D is the correct answer
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So therefore, The correct answer choice from the statement above about investigated factors from lab results is :
Students who spend less time studying after school get lower math grade
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Because the decomposition is the reverse process of the formation.
Enthalpy is a function of state, which means that the value dependes only on the state and not the pathway.
Then the change of enthalpy is the same in magnitude for both cases but in formation the change is netavie (releases energy) and in the other is postive (absorbs energy).
It’s an element because oxygen is already a gas.
Answer:
- 
- 
Explanation:
Hello,
In this case, by considering the dissolution of silver bromide:
![AgBr(s)\rightleftharpoons Ag^+(aq)+Br^-(aq) \ \ \ Ksp=[Ag^+][Br^-]=7.7x10^{-13}](https://tex.z-dn.net/?f=AgBr%28s%29%5Crightleftharpoons%20Ag%5E%2B%28aq%29%2BBr%5E-%28aq%29%20%5C%20%5C%20%5C%20Ksp%3D%5BAg%5E%2B%5D%5BBr%5E-%5D%3D7.7x10%5E%7B-13%7D)
And the formation of the complex:
![Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)\ \ \ Kf=\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}=1.6x10^7](https://tex.z-dn.net/?f=Ag%5E%2B%28aq%29%2B2NH_3%28aq%29%5Crightleftharpoons%20Ag%28NH_3%29_2%5E%2B%28aq%29%5C%20%5C%20%5C%20Kf%3D%5Cfrac%7B%5BAg%28NH_3%29_2%5E%2B%5D%7D%7B%5BAg%5E%2B%5D%5BNH_3%5D%5E2%7D%3D1.6x10%5E7)
We obtain the balanced net ionic equation by adding the aforementioned equations:
Now, the equilibrium constant is obtained by writing the law of mass action for the non-simplified net ionic equation:
![AgBr(s)+Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-+Ag^+\\\\K=[Ag^+][Br^-]*\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}](https://tex.z-dn.net/?f=AgBr%28s%29%2BAg%5E%2B%28aq%29%2B2NH_3%28aq%29%5Crightleftharpoons%20Ag%28NH_3%29_2%5E%2B%28aq%29%2BBr%5E-%2BAg%5E%2B%5C%5C%5C%5CK%3D%5BAg%5E%2B%5D%5BBr%5E-%5D%2A%5Cfrac%7B%5BAg%28NH_3%29_2%5E%2B%5D%7D%7B%5BAg%5E%2B%5D%5BNH_3%5D%5E2%7D)
So we notice that the equilibrium constant contains the solubility constant and formation constant for the initial reactions:
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