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dalvyx [7]
3 years ago
7

What are the word equations for the following? Please help

Chemistry
2 answers:
REY [17]3 years ago
5 0

Answer:

1. CaO + H2O _____ Ca(OH)2

Calcium oxide + Water _____ Calcium hydroxide

2. 2 HCI + MG _____ MgCl2 + H2

Magnesium + hydrochloric acid _____ Magnesium Chloride + hydrogen gas

Serga [27]3 years ago
4 0

Calcium oxide + water = calcium hydroxide.

Magnesium + hydrochloric acid = magnesium chloride + hydrogen.

Sodium hydrogen carbonate + citric acid  = Na3C6H5O7(aq)+3H2O(l)+3CO2(g)

Iron + salt water = 4Fe(OH)3 (rust)

You might be interested in
C5H9O+O2=CO2+H2O balance equation
Gre4nikov [31]
2 C5H12O + 15 O2 = 10 CO2 + 12 H2O

Hope this helped :)
5 0
3 years ago
Describe the nucleus of the atom. Include a description of its size relative to the rest of the atom.
faust18 [17]

Answer:

The nucleus is the most densely compacted part of the atom, it is in the center circled by the electron cloud or shells. It is filled with positively charged protons, and neutrons which have no charge. It is smaller than the electron cloud in size, but in quantity it has more subatomic particles since protons and electrons are equal and the nucleus has nuetrons

6 0
4 years ago
What is the energy of a photon of violet light with a frequency of 7.57x10^14 s^-1?
Eddi Din [679]

Answer:

ΔE = 5.02 x 10⁻¹⁹ j

Explanation:

ΔE (photon) = h·f = (6.63 x 10⁻³⁴ j·s)(7.57 x 10¹⁴ s⁻¹) = 5.02 x 10⁻¹⁹ j

h = Planck's Constant = 6.63 x 10⁻³⁴ j·s

f = frequency (given) = 7.57 x 10¹⁴ s⁻¹

6 0
3 years ago
a gas that has a volume of 28 liters a temperature of 45 c and an unknown pressure has its volume increased to 34 liters and its
emmasim [6.3K]

Answer:

2.52 atm

Explanation:

Change C to K.

Solve for P1=P2V2T2/V1T1

- Hope that helps! Please let me know if you need further explanation.

5 0
4 years ago
A sample of gas occupies 6. 8 L at 327 c what will be it volume at 27 c if the pressure and number of particles do not change
Vitek1552 [10]

A sample of gas occupies 6. 8 L at 327 c and the volume at 27 c if the pressure and number of particles do not change is 3.401 L.

<h3>What is volume?</h3>

Volume is a measurement of the three-dimensional space that is occupied. Numerous imperial units or the SI-derived units, such as the cubic meter and liter, are frequently used to quantify it numerically (such as the gallon, quart, cubic inch). Volume and the length (cubed) have a symbiotic relationship. The volume of a container is typically thought of as its capacity, not as the amount of the space it takes up. In the other words, the volume is the amount of fluid (liquid or gas) that the container may hold.

Volume was initially measured using naturally occurring vessels of a comparable shape and then with standardized containers. Arithmetic formulas can be used to quickly calculate the volume of the several straightforward three-dimensional shapes. If a formula for shape's boundary is known, it is possible to use integral calculus to determine the volumes of more complex shapes. No object in dimensions of zero, one, or two has volume; in the dimensions of four and above, the hypervolume is a concept similar to the standard volume.

In solving the any gas law problems, kelvin temperature will be used.

kelvin = degree celsius + 273.15

Kelvin = 327 + 273.15

                  = 600.15 K

Kelvin = 27 + 273.15

                  =  300.15 K

Given Data;

V_{1}(the initial volume) = 6.8 L                V_{2} (the final volume) = ? unknown

T_{1}(the initial temperature = 327 °C      T_{2}(the final temperature) = 27 °C

                                   =( 600.15 K)                                      = (300.15 K)

This problem can be solve using the Charles' Law which states that volume is directly proportional to kelvin temperature of gases if amount of gas and pressure are constant. If the temperature decreases, volume decreases.

Formula of the Charles' Law is \frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }

To solve for V2, we can used formula V_{2} =\frac{V_{1}T_{2}  }{T_{1} }

V_{2} =\frac{V_{1}T_{2}  }{T_{1} }

    = 6.8 L × 300.15 K / 600.15 K       (cancel the unit kelvin)

    = 2041.02 L / 600.15

V_{2}= 3.401 L

Therefore, volume is 3.401 L

To know more about volume visit: brainly.com/question/1578538

#SPJ4

5 0
1 year ago
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