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3 years ago

Why do liquids solidify when cooled

Physics

2 answers:

Lena [83]3 years ago

5 0

Because the liquid loses its kinetic energy and the particles in the liquid begin to slow down.

Zinaida [17]3 years ago

3 0

Because when liquids are cooled the molecules slow down and that causes liquids to freeze

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What are the methods of storing tools

irina [24]

You might want to visit this website
https://www.nedcc.org/free-resources/preservation-leaflets/4.-storage-and-handling/4.1-storage-metho...

8 0

3 years ago

A group of students put a ford focus in neutral and push the car with 500 N of force to the right, causing the car to travel a d

SOVA2 [1]

50 meters is the answer

4 0

3 years ago

What can be the maximum value of the original kinetic energy of disk AA so as not to exceed the maximum allowed value of the the

timurjin [86]

The question is incomplete. The complete question is :

In your job as a mechanical engineer you are designing a flywheel and clutch-plate system. Disk A is made of a lighter material than disk B, and the moment of inertia of disk A about the shaft is one-third that of disk B. The moment of inertia of the shaft is negligible. With the clutch disconnected, A is brought up to an angular speed ?0; B is initially at rest. The accelerating torque is then removed from A, and A is coupled to B. (Ignore bearing friction.) The design specifications allow for a maximum of 2300 J of thermal energy to be developed when the connection is made. What can be the maximum value of the original kinetic energy of disk A so as not to exceed the maximum allowed value of the thermal energy?

Solution :

Let M.I. of disk A = $I_0$

So, M.I. of disk B = $3I_0$

Angular velocity of A = $\omega_0$

So the kinetic energy of the disk A = $\frac{1}{2}I_0\omega^2$

After coupling, the angular velocity of both the disks will be equal to ω.

Angular momentum will be conserved.

So,

$I_0\omega_0 = I_0 \omega + 3I_0 \omega$

$I_0\omega_0 = 4I_0 \omega$

$\omega = \frac{\omega_0}{4}$

Now,

$K.E. = \frac{1}{2}I_0\omega^2+ \frac{1}{2}3I_0\omega^2$

$K.E. = \frac{1}{2}I_0\frac{\omega_0^2}{16}+ \frac{1}{2}3I_0\frac{\omega_0^2}{16}$

$K.E. = \frac{1}{2}I_0\omega_0^2 \left(\frac{1}{16}+\frac{3}{16}\right)$

$K.E. = \frac{1}{2}I_0\omega_0^2\times \frac{1}{4}$

$\Delta K = \frac{1}{2}I_0\omega_0^2 - \frac{1}{2}I_0\omega_0^2 \times \frac{1}{4}$

$2300=\frac{3}{4}\left(\frac{1}{2}I_0\omega_0^2\right)$

$\frac{1}{2}I_0\omega_0^2=2300 \times \frac{4}{3 } \ J$

Therefore, the maximum initial K.E. = 3066.67 J

3 0

3 years ago

Different types of waves travel at different speeds. For example, sound waves travel more slowly than light waves. Have you ever

trapecia [35]

Answer:

A). Light moves faster than sound, so you hear thunder after you see lightning.

Explanation:

The lightning and thunder demonstrate that 'light travels faster than sound' which clearly portrays the relationship between the light and the soundwaves. When we see lightning in the sky before hearing the sound of thunder as the speed of light much higher than the speed of sound. Sound travels ~ 343 m/s or 1235 km/hr while light travels 300000 km/s. This difference in speed prevents us from considering lightning and thunder as the same thing. The 'sound is a pressure wave and therefore, takes time to travel and bounce back to our ears.' Thus, we happen to witness lightning first. Hence, <u>option A</u> is the correct answer.

3 0

3 years ago

An acceleration of a freely falling body (9.8m/s^2) to ft/s^2

Ronch [10]

9.8 m/s^2 = 32.2 ft/s^2

hope this helps :)

5 0

3 years ago