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andrezito [222]
3 years ago
8

How dense the medium is in the compression part of the wave, and how

Physics
1 answer:
ivolga24 [154]3 years ago
4 0
How dense the medium is in the compression part of the wave and how rare the medium is in the rarefaction part of the wave is a measure of the longitudinal wave's amplitude.
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Which standing wave has four antibodies?
frez [133]

Answer:

Term (symbol) Meaning

Standing wave Waves which appear to be vibrating vertically without traveling horizontally. Created from waves with identical frequency and amplitude interfering with one another while traveling in opposite directions.

Node Positions on a standing wave where the wave stays in a fixed position over time because of destructive interference.

Antinode Positions on a standing wave where the wave vibrates with maximum amplitude.

Fundamental frequency Lowest frequency of a standing wave that has the fewest number of nodes and antinodes.

Harmonic A standing wave that is a positive integer multiple of the fundamental frequency.

Explanation:

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A box slides to the right along a horizontal surface which is true about the friction force
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Answer:

It is a force in the direction of the motion that allows the box to move

Explanation:

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There is T__ as much voltage. This<br> produces twice the current
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Twice as much voltage
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A gas station owner suspects that he is being overcharged for gasoline deliveries by a gasoline supplier. The overcharge seems p
Tems11 [23]

Answer:

Explanation:

delta V = v * alpha * delta T

= V * 0.00053 * (92.2 - 55.0)

= 0.019716 V

percentage that the owner

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= [0.019716 V / V] * 100

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4 0
2 years ago
A bowling ball of mass m=1.7kg is launched from a spring compressed by a distance d=0.31m at an angle of theta=37 measured from
vodomira [7]

Answer:

k = 1 700.7 N/m

v0 = 9.8 m/s^2

Explanation:

Hello!

We can answer this question using conservation of energy.

The potential energy of the spring (PS) will transform to kinetic energy (KE) of the ball, and eventually, when the velocity of the ball is zero, all that energy will be potential gravitational (PG) energy.

When the kinetic energy of the ball is zero, that is, when it has reached its maximum heigh, all the potential energy of the spring will be equal to the potential energy of the gravitational field.

PS = (1/2) k x^2  <em>where x is the compresion or elongation of the spring</em>

PG = mgh

a)

Since energy must be conserved and we are neglecting any energy loss:

PS = PG

Solving for k

k = (2mgh)/(x^2) = ( 2 * 1.7 * 9.81 * 4.9 Nm)/(0.31^2 m^2)

k = 1 700.7 N/m

b)

Since the potential energy of the spring transfors to kinetic energy of the ball we have that:

PS = KE

that is:

(1/2) k x^2 = (1/2) m v0^2

Solving for v0

v0 = x √(k/m) = (0.31 m ) √( 1 700.7 N/m / 1.7kg)

v0 = 9.8 m/s^2

8 0
3 years ago
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