Explanation:
It is known that relation between
,
, and pH is as follows.
![E_{cell} = E^{o}_{cell} - (\frac{0.0591}{n}) \times log[H^{+}] ](https://tex.z-dn.net/?f=E_%7Bcell%7D%20%3D%20E%5E%7Bo%7D_%7Bcell%7D%20-%20%28%5Cfrac%7B0.0591%7D%7Bn%7D%29%20%5Ctimes%20log%5BH%5E%7B%2B%7D%5D%0A)
Also, it is known that
for hydrogen is equal to zero.
Hence, substituting the given values into the above equation as follows.
![E_{cell} = E^{o}_{cell} - (\frac{0.0591}{n}) \times log[H^{+}] ](https://tex.z-dn.net/?f=E_%7Bcell%7D%20%3D%20E%5E%7Bo%7D_%7Bcell%7D%20-%20%28%5Cfrac%7B0.0591%7D%7Bn%7D%29%20%5Ctimes%20log%5BH%5E%7B%2B%7D%5D%0A)
0.238 V = 0 - (\frac{0.0591}{1}) \times log[H^{+}]
[/tex]
= 4.03
= antilog 4.03
= 3.5
As, pH =
.
Thus, we can conclude that pH of the given unknown solution at 298 K is 3.5.
Boyle's Law
P1V1 = P2V2
1.8 atm * 2.5 L = P2 * 1.2 L
1.8 atm * 2.5 L / 1.2 L = P2
3.75 atm = P2
Using significant digits, the answer is 3.8 atm
Tin to Fluorine mass ratios:
1) For compound A:
38.5/12.3
= 3.13
2) For compound B:
56.5/36.2
= 1.56
The lowest whole number mass ratio is 2. It cannot be 1 because it is less than that required for compound B.
15.0 moles of silver chloride are produced.