Question

A particle executes simple harmonic motion

Answer 1

The positive displacement x = 0.27 cm.

Explanation:

The formula to calculate displacement of a particle executing simple harmonic motion is given by,

                                   x  =  A s i n ( ω t )

where x represents the displacement,

          A represents the amplitude,

          ω represents the angular frequency,

           t represents the time.

Given, amplitude A = 3.43 cm,   t = 1 / 2  = 0.5 s

                                  x = A s i n ( ω t )

Since ω = 2πf,

                                  x = 3.43 sin (2$\times$3.14$\times$50$\times$0.5)

                                     = 3.43 sin(157)

                                  x = 0.27 cm.