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2 years ago

If a water wave completes one cycle in 2 seconds, what is the period of the wave?

2 answers:

8 0

The definition of the period of a wave is the time that it takes for the wave to complete one cycle. As stated in the problem, the certain water wave completes one cycle in 2 seconds. From this information alone, we can conclude that the period of the wave is indeed, 2 seconds.

Alex2 years ago

3 0

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What is the initial velocity and final velocity<br> h

IceJOKER [234]

Answer:

initial velocity =starting velocity

final velocity=last velocity

keep in mind the fact that velocity is a vector quantity it also has a direction

8 0

2 years ago

Car 1 goes around a level curve at a constant speed of 65 km/h . The curve is a circular arc with a radius of 95 m . Car 2 goes

Arte-miy333 [17]

Answer:

The radius of the curve that Car 2 travels on is 380 meters.

Explanation:

Speed of car 1, $v_1=65\ km/h$

Radius of the circular arc, $r_1=95\ m$

Car 2 has twice the speed of Car 1, $v_2=130\ km/h$

We need to find the radius of the curve that Car 2 travels on have to be in order for both cars to have the same centripetal acceleration. We know that the centripetal acceleration is given by :

$a=\dfrac{v^2}{r}$

According to given condition,

$\dfrac{v_1^2}{r_1}=\dfrac{v_2^2}{r_2}$

$\dfrac{65^2}{95}=\dfrac{130^2}{r_2}$

On solving we get :

$r_2=380\ m$

So, the radius of the curve that Car 2 travels on is 380 meters. Hence, this is the required solution.

4 0

3 years ago

A train Traveled from hong kong to beijing. It traveled at an average speed of 160 km/h in the first four hours. After that, it

4vir4ik [10]

The answer is 7 hours

3 0

3 years ago

A go-cart and rider have a mass of 14 kg. If the cart accelerates at 6m/s^2 during a 40 m sprint in 100 seconds, how much power

lara [203]

Answer:

P = 33.6 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 14 [kg]

a = acceleration = 6 [m/s²]

$F = 14*6\\F = 84 [N]$

In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.

$W = F*d$