Answer:
The magnitude of the angular momentum of the Mars in a circular orbit around the sun is ![3.53\times10^{39}\ kg-m^2/s](https://tex.z-dn.net/?f=3.53%5Ctimes10%5E%7B39%7D%5C%20kg-m%5E2%2Fs)
Explanation:
Given that,
Mass of mars ![M=6.42\times10^{23}\ kg](https://tex.z-dn.net/?f=M%3D6.42%5Ctimes10%5E%7B23%7D%5C%20kg)
Radius ![r'= 3.40\times10^{6}](https://tex.z-dn.net/?f=r%27%3D%203.40%5Ctimes10%5E%7B6%7D)
Orbit radius ![r=2.28\times10^{11}\ m](https://tex.z-dn.net/?f=r%3D2.28%5Ctimes10%5E%7B11%7D%5C%20m)
Time period = 687 days
We need to calculate the magnitude of the angular momentum of the mars
Using formula of angular momentum
![L = I\omega](https://tex.z-dn.net/?f=L%20%3D%20I%5Comega)
Here, ![I = mr^2](https://tex.z-dn.net/?f=%20I%20%3D%20mr%5E2)
![L=mr^2\omega](https://tex.z-dn.net/?f=%20L%3Dmr%5E2%5Comega)
![L=mr^2\times\dfrac{2\pi}{T}](https://tex.z-dn.net/?f=%20L%3Dmr%5E2%5Ctimes%5Cdfrac%7B2%5Cpi%7D%7BT%7D)
Where,
L = angular momentum
I = moment of inertia
r = radius
=angular speed
Put the value into the formula
![L=6.42\times10^{23}\times(2.28\times10^{11})^2\times\dfrac{2\pi}{687\times24\times3600}](https://tex.z-dn.net/?f=L%3D6.42%5Ctimes10%5E%7B23%7D%5Ctimes%282.28%5Ctimes10%5E%7B11%7D%29%5E2%5Ctimes%5Cdfrac%7B2%5Cpi%7D%7B687%5Ctimes24%5Ctimes3600%7D)
![L=3.53\times10^{39}\ kg-m^2/s](https://tex.z-dn.net/?f=L%3D3.53%5Ctimes10%5E%7B39%7D%5C%20kg-m%5E2%2Fs)
Hence, The magnitude of the angular momentum of the Mars in a circular orbit around the sun is ![3.53\times10^{39}\ kg-m^2/s](https://tex.z-dn.net/?f=3.53%5Ctimes10%5E%7B39%7D%5C%20kg-m%5E2%2Fs)
Answer:
it is placed 9th in the periodic table
it is in the the 7th column and the 2nd period
it is a gas
it valence shell has 7 electrons and it can take 1 electron during ionic bonding
Explanation:
this is all that can into my mind. hope it helps
Answer:
All object changes are compared with a <em>reference</em> , which is an object that appears to stay in place.
Explanation:
In scientific experiments, the changes in the experimental object are observed by comparing the changes with a reference object. In the reference object, no changes are made and conditions are kept normal in it. For example, if we want to measure the distance of two cars from a point, the point will be the reference point from which the distance shall be measured. Hence, all changes are made by comparison from a reference object or point.
That all depends on what kind of quantity you are graphing.
It might be speed, temperature, altitude, relative humidity,
barometric pressure, etc. Each would use a different unit.
Not sure this is a physics question (probably biology).
Anyway, the correct answer is A):
"Plasticity helps us to adapt to our environment. It also generally decreases with age".
Plasticity is the ability to adapt to the environment. Since this ability is linked with brain functions, and brain functions worsen with age, then plasticity decreases with age.