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anyanavicka [17]
2 years ago
6

If a water wave completes one cycle in 2 seconds, what is the period of the wave?

Physics
2 answers:
Anika [276]2 years ago
8 0
The definition of the period of a wave is the time that it takes for the wave to complete one cycle. As stated in the problem, the certain water wave completes one cycle in 2 seconds. From this information alone, we can conclude that the period of the wave is indeed, 2 seconds. 
Alex2 years ago
3 0

The definition of the period of a wave is the time that it takes for the wave to complete one cycle. As stated in the problem, the certain water wave completes one cycle in 2 seconds. From this information alone, we can conclude that the period of the wave is indeed, 2 seconds



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Consider a system of a cliff diver and the earth. the gravitational potential energy of the system decreases by 28,000 j as the
olga2289 [7]

The decrease in gravitational potential energy of the system is given by

\Delta U = (mg) \Delta h

where

m is the mass, g is the gravitational acceleration, and \Delta h is the variation of height of the system.


(mg) also corresponds to the weight of the diver, therefore if we rearrange the equation and we use \Delta U=28000 J and \Delta h=32.0 m, we can find her weight:

mg=\frac{\Delta U}{\Delta h}=\frac{28000 J}{32 m}=875 N

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3 years ago
It has been argued that power plants should make use of off-peak hours (such as late at night) to generate mechanical energy and
Trava [24]

Answer:

Explanation:

kinetic energy = 14.1 MJ = 14.1 x 10⁶ J

Let radius of flywheel be r .

volume of flywheel = π r² x t where t is thickness

= 3.14 x r² x .113 m³

= .04 r² m³

mass = volume x density

= .04 r² x 7800 = 312.73 r²kg

moment of inertia I = 1 / 2 mass x radius²

= .5 x 312.73 r² x r²

= 156.37 r⁴ kg m²

angular velocity ω = 2π x 93/60

= 9.734 rad /s

kinetic energy = 1/2 Iω² where ω is angular velocity

= .5 x 156.37 r⁴ x 9.734²

= 7408.08 r⁴

Given

7408.08 r⁴ =  14.1 x 10⁶

r⁴ = .19 x 10⁴

r = .66 x 10

= 6.60 m .

Diameter = 13.2 m

b )

centripetal acceleration of a point on its rim = ω² r

= 9.734² x 6.6

= 625.35 m /s²

5 0
3 years ago
Why do we need to square the period for pendulum experiment? How it is related to obtaining gram ?
andreev551 [17]

Answer:

The period of a pendulum does not depend on the mass of the ball, but only on the length of the string. Two pendula with different masses but the same length will have the same period. Two pendula with different lengths will different periods; the pendulum with the longer string will have the longer period.

Explanation:

6 0
2 years ago
A driver averaged 64 mph and took 3½ hours to travel from st. Louis to chicago. Based on this, what is the distance between st.
sammy [17]

Average speed of the driver is given as

v = 64 mph

if he moved for total time t = 3.5 hours

so the distance between the tow is given as

d = v* t

d = 64 * 3.5

d = 224 miles

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6 0
3 years ago
If the strength of the magnetic field at A is 200 units and the strength of the magnetic field at B is 50 units, what is the dis
Whitepunk [10]
A is the answer!!!!!!!!!!!!!!!!!!
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