Answer:
mass of platinum = 2526.12 g
Explanation:
Given data:
Mass of water = 125 g
Initial temperature of water= 100.0°C
Initial temperature of Pt = 20.0°C
Final temperature = 235°C
Specific heat of Pt = 0.13 j/g°C
Specific heat of water = 4.184 j/g°C
Mass of platinum = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
Q(w) = Q(Pt)
m.c. (T2 - T1) = m.c.
(T2 - T1)
125 g × 4.184 j/g°C × (235°C - 100.0°C) = m × 0.13 j/g°C × (235°C - 20°C)
125 g × 4.184 j/g°C × 135°C = m × 0.13 j/g°C × 215°C
70605 j = m×27.95 j/g
m = 70605 j /27.95 j/g
m = 2526.12 g
The ph of a solution is 3.7
Solution:
According to the equaiton of Henderson-Hasselback
pH= pKa+ log(salt/acid)
here it is given the value of
pKa= 4.7
So,
pH = pKa+ log(0.1/0.01)
= 4.7 + log(0.1)
= 4.7–1
= 3.7.
The following problem illustrates how the Henderson-Hasselbalch equation can be used to determine how much acid and conjugate base should be combined to create a buffer solution with a specific pH.
To learn more click the given link
brainly.com/question/13423434
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If you are talking about bonds they are influenced by electronegativity and how many valence electrons they have.
