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guajiro [1.7K]
3 years ago
8

Buffer systems present in blood help in maintaining the neutral pH of blood. Which is the most important buffer system present i

n blood? A.Carbon monoxide-hydrogen buffer. B. Carbonic acid-bicarbonate buffer. C.Carbon dioxide-bicarbonate buffer
Chemistry
2 answers:
Alona [7]3 years ago
5 0

The correct option is B.

A buffer refers to an aqueous solution which resist changes in pH when acids or bases are added to it. Also addition or removal of water from a buffer system does not change the pH of the system significantly. Buffers typically are made up of pairs of weak acid and their conjugate base or pairs of weak base and their conjugate acids. Maintaining the ideal pH is very important in living organisms, blood buffers help living organisms to maintain constant blood pH.

rjkz [21]3 years ago
5 0
I think the correct answer from the choices listed above is option B. Buffer systems present in blood help in maintaining the neutral pH of blood. The most important buffer system is the Carbonic acid-bicarbonate buffer. Hope this answers the question.
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Which of the following is the number of moles of solute that is dissolved in 1 liter of solution?
Komok [63]
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4 0
3 years ago
Solid a is a very hard electrical insulator in solid as well as in molten state and melts at extremely high temperature. What ty
velikii [3]

This is covalent network type of solid.

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3 0
2 years ago
A single atom is in a balanced electrical state.
slega [8]
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7 0
3 years ago
Read 2 more answers
A drop of water weighing 0.48 g is vaporized at 100 ?c and condenses on the surface of a 55-g block of aluminum that is initiall
irakobra [83]
<h3><u>Answer;</u></h3>

<em>-49 °C</em>

<h3><u>Explanation and solution;</u></h3>
  • Considering the fact that, the specific heat capacity of aluminum is 0.903 J/g x C, and the heat of vaporization of water at 25 C is 44.0 KJ/mol.  

Moles water = 0.48 g / 18.02 g/mol

                      =0.0266  moles

<em>Heat lost by water</em> = 0.0266 mol x 44.0 kJ/mol

                                 =1.17 kJ => 1170 J  

<em>But heat lost =heat gained</em>

<em>Therefore;</em> Heat gained by aluminium = 1170 J  

        1170 = 55 x 0.903 ( T - 25) = 49.7 T - 1242  

                   1170 + 1242 = 49.7 T  

            T = 48.5 °C ( 49 °C <em>at two significant figures)</em>

<em>Hence</em>, final temperature = 49 °C

4 0
3 years ago
Read 2 more answers
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