If the vertical posts supporting these wires divide the lines into straight 19.0 m segments, what magnetic force does each segme
nt exert on the other?
1 answer:
Answer:
Complete question is:
Two high-current transmission lines carry currents of 29.0 A and 78.0 A in the same direction and are suspended parallel to each other 38.0 cm apart.
Part A.) If the vertical posts supporting these wires divide the lines into straight 20.0m segments, what magnetic force does each segment exert on the other? (answer in F= ? N)
Part B.) Is the force found in part (A) attractive or repulsive?
Answer: 0.024 N attraction force is being applied.
Explanation:
See attached picture.
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Answer:
≈ 2.1 R
Explanation:
The moment of inertia of the bodies can be calculated by the equation
I = ∫ r² dm
For bodies with symmetry this tabulated, the moment of inertia of the center of mass
Sphere = 2/5 M R²
Spherical shell = 2/3 M R²
The parallel axes theorem allows us to calculate the moment of inertia with respect to different axes, without knowing the moment of inertia of the center of mass
I = + M D²
Where M is the mass of the body and D is the distance from the center of mass to the axis of rotation
Let's start with the spherical shell, axis is along a diameter
D = 2R
Ic = + M D²
Ic = 2/3 MR² + M (2R)²
Ic = M R² (2/3 + 4)
Ic = 14/3 M R²
The sphere
Is = + M [
²
Is = Ic
2/5 MR² + M ² = 14/3 MR²
² = R² (14/3 - 2/5)
= √ (R² (64/15)
= 2,066 R