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Anvisha [2.4K]
3 years ago
8

Why is acceleration called vector quantity

Physics
1 answer:
MrRissso [65]3 years ago
7 0
Because it has both magnitude and direction. When an object has positive acceleration, the acceleration occurs in the same direction as the movement of the object.
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4. Which of the following would be a good reference point to describe the motion of a dog?
saul85 [17]

ANOTHER RUNNING DOG

Explanation:

In the given question it is to find a suitable reference point to describe  the motion of dog. Here I could suggest that it is better to compare the dog with  another running dog to create the relative speed difference to get a reliable motion variation.

Because the motion of dog is in the linear with respect to the another dog and to the acceleration produced by the dog in the required interval is easy to calculate with respect to  another dog which is already in motion.

Hence, I suggest that Motion of dog can be analysed better by analyse the motion variation of dog with  another dog running.

4 0
3 years ago
What force is required to accelerate a 1840 kg car from 4.77 m/s to 23.5 m/s,
neonofarm [45]
A :-) for this question , we should apply
a = v - u by t
Given - u = 4.77 m/s
v = 23.5 m/s
t = 5.18 m/s
Solution -
a = v - u by t
a = 23.5 - 4.77
a = 28.27 m/s^2

.:. The acceleration is 28.27 m/s^2
7 0
3 years ago
A proton moving at 3.90 106 m/s through a magnetic field of magnitude 1.80 T experiences a magnetic force of magnitude 7.20 10-1
VARVARA [1.3K]

Answer:

\theta=40^0

Explanation:

The magnitude of the magnetic force is

F_m=evB\sin\theta

To find the angle, we make \sin\theta subject of the formula

\implies \sin\theta=\frac{F_m}{evB}=\frac{7.20\times 10^{-13}}{1.6\times 10^{-19}\times 3.90\times 10^6\times 1.80}

\implies \sin\theta=0.641025641

\therefore \theta=\sin^{-1}=39.8683^0\\\implies \theta\approxeq 40^0

8 0
3 years ago
The transverse standing wave on a string fixed at both ends is vibrating at its fundamental frequency of 250 Hz. What would be t
hodyreva [135]

Answer:

Explanation:

fundamental frequency, f = 250 Hz

Let T be the tension in the string and length of the string is l ans m be the mass of the string initially.

the formula for the frequency is given by

f=\frac{1}{2l}\sqrt{\frac{Tl}{m}}    .... (1)

Now the length is doubled ans the tension is four times but the mass remains same.

let the frequency is f'

f'=\frac{1}{2\times 2l}\sqrt{\frac{4T\times 2l}{m}}    .... (2)

Divide equation (2) by equation (1)

f' = √2 x f

f' = 1.414 x 250

f' = 353.5 Hz

7 0
3 years ago
One complete expression of a waveform beginning at a certain point, progressing through the zero line to the wave’s highest (cre
elixir [45]

Answer:

wavelength.

Explanation:

One complete expression of a waveform beginning at a certain point, progressing through the zero line to the wave’s highest (crest) and lowest (trough) points, and returning to the same value as the starting point is called a is called wavelength. Its can be also defined as the distance between two successive crests or trough points in wave form.

4 0
3 years ago
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