The force applied by the competitor is littler than the heaviness of the barbell. At the point when the barbell quickens upward, the power applied by the competitor is more prominent than the heaviness of the barbell. When it decelerates upward, the power applied by the competitor is littler than the heaviness of the barbell.
Answer:
(
)=1913.31 N/m^2
Explanation:
given:
=0.85
=90 m/s
γ∞=1.23 kg/m^3
solution:
since outside pressure is atm pressure vaccum can be defined by ()
=√2()/γ∞[
-1]
()=1913.31 N/m^2
Because it can pollute the air and cause wild life to eat stuff that has been contimanted by the air
Correct me if I’m wrong but I think it’s A
Explanation:
Runner A has already reached about 50m in around 5s.
Relative to the floor it's resting on, its height is zero,
so its potential energy is zero.
Relative to the next floor down, its height could be
three or four meters, and it could have plenty of
potential energy ... if you cut out a circle in the floor
all around the rock, and let it fall to next floor down,
it could really do some damage. Look out below ! !
