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Jobisdone [24]
3 years ago
11

Which part of earths surface has the greatest rotational speed

Physics
1 answer:
Anni [7]3 years ago
6 0
Every point on the surface must have the same rotational speed.
Otherwise some places would rotate away from other places.

If the next block of your city rotated faster than the block that you live on,
then you could sit at home, look out the window, and watch your school
rotate past your house.

The map of the continents on the Earth would change constantly. 
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PLEASE PLEASE HELP<br> (Picture)
atroni [7]

Answer:

light slows it down

Explanation:

7 0
3 years ago
If a 2 kg spring is compressed by exerting a force of 10 newtons a distance of 50 cm how much work is done?
Elina [12.6K]
Convert cm into meters,
50/100=0.5m

work done= 10x0.5
=5J

we dont consider the weight of the spring as it acts downwards.
5 0
3 years ago
Sound travels faster through rigid material like steel rather than through spongy materials like rubber. Why?
drek231 [11]
<span>since sound travels using mechanical waves and needs a material medium to propagate and since mechanical waves spread through vibrations ...and since hard materials have their atoms packed closely....they need to vibrate with a smaller amplitude to pass on the wave....thus sound travels faster in a denser medium than a less dense one.</span>
3 0
3 years ago
magnitude of velocity does not change but the direction changes. Can we say that it is an accelerated motion?
Olenka [21]

Answer:

MRCORRECT has answered the question

Explanation:

Since velocity is a vector, it can change either in magnitude or in direction. Acceleration is therefore a change in either speed ordirection, or both. Keep in mind that althoughacceleration is in the direction of the changein velocity, it is not always in the direction ofmotion.

4 0
3 years ago
A 0.5 μF and a 11 μF capacitors are connected in series. Then the pair are connected in parallel with a 1.5 μF capacitor. What i
NISA [10]

Answer:

C_{eq}=1.97\ \mu F

Explanation:

Given that,

Capacitance 1, C_1=0.5\ \mu F

Capacitance 2, C_2=11\ \mu F

Capacitance 3, C_3=1.5\ \mu F

C₁ and C₂ are connected in series. Their equivalent is given by :

\dfrac{1}{C'}=\dfrac{1}{C_1}+\dfrac{1}{C_2}

\dfrac{1}{C'}=\dfrac{1}{0.5}+\dfrac{1}{11}

C'=0.47\ \mu F

Now C' and C₃ are connected in parallel. So, the final equivalent capacitance is given by :

C_{eq}=C'+C_3

C_{eq}=0.47+1.5

C_{eq}=1.97\ \mu F

So, the equivalent capacitance of the combination is 1.97 micro farad. Hence, this is the required solution.

3 0
3 years ago
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