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horsena [70]
3 years ago
13

A sample of ammonium chloride (NH4Cl) has 9.8 moles. How many atoms of hydrogen are in the sample?

Chemistry
1 answer:
blondinia [14]3 years ago
6 0

2.360 × 10^25

Explanation:

The only issue that may arise from asking a question like this is not understanding mole ratios:

Imagine 1 mol of CO2:

You need 1 mol of the end result. In the end result, you have:

1 Carbon

2 Oxygens

When you're trying to get 1 mol of the final compound, you need to have:

1 mol Carbon

2 mol Oxygen

If this doesn't make sense, Khan Academy has insightful videos showing how this works.

So, for NH4Cl, ignore everything but the H. We don't care about them.

You need 4 hydrogens to get 1 NH4Cl, so multiply whatever mole value you're given by 4. That's how many moles of hydrogen there are.

9.8 mol × 4 = 39.2mol H

So the next question is, <em>what</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>mole</em><em>?</em><em> </em><em> </em>The answer to this question is the same as asking <em>what</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>dozen</em><em>?</em> Well, it's just a number of things. Instead of 12, like a dozen, it's 6.02×10²³. This is called Avogadro's Number.

So say you have two dozen. You'll do 2 × 12, right?

Say you have 39.2moles. Apply the same idea, except with Avogadro's Number instead of 12:

39.2 × 6.02×10²³ = 2.360 × 10^25

So what <em>is</em><em> </em>this number? It's how many <em>things</em><em> </em>are in 39.2moles. We were calculating individual hydrogens, which are atoms, so this number represents how many atoms there are in 39.2moles.

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Answer:

0.302 moles

Explanation:

Data given

Mass of Pb(NO₃)₂ = 100 g

Moles of Pb(NO₃)₂ = ?

Solution:

To find mole we have to know about molar mass of Pb(NO₃)₂  

So,

Molar mass of Pb(NO₃)₂  = 207 + 2[14 + 3(16)]

                                           = 207 + 2[14 + 48]

                                           = 207 + 124

Molar mass of Pb(NO₃)₂  = 331 g/mol

Formula used :

                no. of moles = mass in grams / molar mass

Put values in above formula

                   no. of moles = 100 g / 331 g/mol

                   no. of moles = 0.302 moles

no. of moles of  Pb(NO₃)₂ = 0.302 moles

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In a single displacement reaction between Sodium Phosphate and Barium, how much of each product (in grams) will be formed from 1
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Answer:

14.6 g of barium phosphate

3.35 g of sodium metal

Explanation:

2Na3PO4(aq) + 3Ba(s) -------> Ba3(PO4)2(aq) + 6Na(s)

The first step in any such reaction is to but down the balanced reaction equation according to the stoichiometry of the reaction.

The two products formed are barium phosphate and sodium metal.

Number of moles of barium corresponding to 10.0g of barium = mass of barium/ molar mass of barium

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Number of moles of barium = 10/137.327

Number of moles of barium = 0.0728 moles

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3 moles of barium yields 1 mole of barium phosphate

0.0728 moles yields 0.0728 moles × 1/3 = 0.0243 moles of barium phosphate

Molar mass of barium phosphate = 601.93 g/mol

Therefore mass of barium phosphate = 0.0243 moles × 601.93 g/mol = 14.6 g of barium phosphate

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3 moles of barium yields 6 moles of sodium metal

0.0728 moles of barium yields 0.0728 × 6 / 3 = 0.1456 moles of sodium

Molar mass of sodium metal= 23 gmol-1

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