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Setler79 [48]
4 years ago
15

*****WORTH 100 POINTS******WILL MARK BRAINLIEST********* Please help

Physics
2 answers:
EastWind [94]4 years ago
8 0

The baby that crawls at a constant speed is Baby molly

Her speed is 1.7

The speed of the other baby is 1.3

Temka [501]4 years ago
6 0

Answer:

The baby that crawls at a constant speed is Baby molly

Her speed is 1.7

The speed of the other baby is 1.3

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1) Calculate the potential energy of a 5.00 kg object sitting on a 3.00 meter high ledge.
maria [59]

Answer:

15kg

Explanation:

5 0
3 years ago
If you had started with a larger mass, how would the half-life change?
iogann1982 [59]

Answer:

There is no change, unless your mass is somehow at the quantum level, at which the concept of half-life breaks down.

Half life is a property of the specific radioactive isotope...NOT of the initial sample's mass.

3 0
3 years ago
The temperature of 1 m^3 of water is decreased by 10°C. If this thermal energy is used to lift the water vertically against grav
Rama09 [41]

Answer:

h = 4271.43 m

Explanation:

given,

Volume of the water = 1 m³

temperature decrease by = 10°C

heat removed from water

Q = m c ΔT                            

Q = ρ V c ΔT                            

   = 1000 × 1 × 4186 × 10

   = 4.186 × 10⁷ J

energy is used to do work to move the water against its weight

Q = force  × displacement

4.186 × 10⁷ J =  m g × h                    

4.186 × 10⁷ J =  1000 × 1 × 9.8 × h                

h = 4271.43 m                                

hence, the change in height of is equal to h = 4271.43 m

8 0
4 years ago
an open rectangular tank 1.0 meter wide and 2.0 meter long contains gasoline to a depth of 1.5 meters. if the height of the tank
Alekssandra [29.7K]

The maximum horizontal acceleration is solved to be 4.91 m/s^2

<u />

<h3>What is acceleration?</h3>

This is a term in physics that refers to change in velocity with time.  Acceleration can be positive or negative or zero,

<u />

<u>Given data</u>

open rectangular tank

width = 1.0 m

length = 2.0 m

gasoline depth level = 1.5 m

height of the tank = 2.0 m

<h3>How to solve for maximum horizontal acceleration</h3>

lets represent the volume with x, y, and z such that z corresponds to height, y corresponds to wide or width, and x corresponds to length.  

dz / dy = - ay / ( g + az )

where

ay = acceleration in the y direction

az = acceleration in the z direction which is equal to zero

g = acceleration due to gravity

plugging in az = 0

dz / dy = - ay / ( g )

ay = - ( dz / dy ) * g

to prevent spilling

dz / dy = -  ( 1.5 - 1 ) / 1

dz / dy = -  0.5

ay = - ( - 0.5 ) * 9.81

ay = 4.91 meters per second square

Hence the maximum horizontal acceleration is solved to be 4.91 m/s^2

Read more on acceleration here: brainly.com/question/605631

#SPJ1

7 0
2 years ago
A cubic box of volume 5.1 x 10 -2m3 is
I am Lyosha [343]

Answer:

21544 N

Explanation:

Let the atmospheric pressure be 101325 Pa

The side length of the cubic box:

V = d^3 = 0.051m^3

d = \sqrt[3]{V} = \sqrt[3]{0.051} = 0.371 m

The area of the cubic box:

A = d^2 = 0.371^2 = 0.1375 m^2

20 C = 20 + 273 = 293 K

180 C = 180 + 273 = 453 K

As the volume of the air inside the closed cube is not changed, assume the ideal gas law we have

\frac{P_1}{T_1} = \frac{P_2}{T_2}

Where P1 = 101325 Pa and T1 = 293K are the original atmospheric pressure and temperature. P2 and T2 = 453 are the new pressure and temperature after the cube gets heat up

P_2 = P_1\frac{T_2}{T_1} = 101325\frac{453}{293} = 156656 Pa

The net force on each side of the box it its pressure times side area

F = P_2A = 156656 * 0.1375 = 21544 N

8 0
3 years ago
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