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Hoochie [10]
3 years ago
11

Science, who ever answers this will get a brainlest

Physics
2 answers:
Ganezh [65]3 years ago
8 0

answer:

a.fossils of the same plants and animals are found on widely spread continents

explanation:

four fossil examples include; the mesosaurus, cynognathus, lystrosaurus, and glossopteris.

good luck :)

i hope this helps

have a nice day !!

musickatia [10]3 years ago
7 0
The first one(about the spread fossils).
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What's the concept of mass ?
Marat540 [252]
Masa is a concept that identifies that magnitude of a physical nature that allows indicating the amount of matter in a body. Within the International System , its unit is the kilogram ( kg . ) 
6 0
3 years ago
An engineer wishes to design a roller coaster so that
nataly862011 [7]

To prevent cars from falling, the radius at the top of the circle should be

small such cars inverted at the top remain attached during motion.

Correct response;

The radius of the coaster can be <u>C) 20 m</u>

<h3>Method by which the above option is selected</h3>

Mass of roller coaster car, m = 500 kg

Speed at the top of the circle, v = 20 m/s

Required:

The maximum radius of the circular path the roller coaster car.

Solution:

\displaystyle Centrifugal \ force, \, F_{c} = \mathbf{\frac{m \cdot v^2}{r}}

Where;

r = The radius of the circular path.

Weight of the roller coaster car = m·g = The centripetal force

Where;

g = Acceleration due to gravity = 9.81 m/s²

At equilibrium, we have;

Centrifugal force = Centripetal force

\displaystyle \frac{m \cdot v^2}{r}  = \mathbf{ m \cdot g}

Therefore;

\displaystyle r = \mathbf{ \frac{v^2}{g}}

Which gives;

\displaystyle r = \frac{20^2}{9.81} \approx 40.77

The maximum radius for safety of a roller coaster, r ≈ 40.77 meters

\displaystyle Range \ of \ radius \ of \ the \ circle = \frac{40.77}{4}  \leq Radius \ of \ circle \leq 40.77

Which gives;

Range of the radius of the circle = 10.2 ≤ Radius of circle ≤ 40.77

The correct option for safety considerations is therefore;

  • <u>C) 20 m</u>

<em>The possible question options are;</em>

<em>A) 5 m  B) 10 m  C) 20 m  D) 40 m  E) 80 m</em>

Learn more about centripetal force here:

brainly.com/question/12674230

7 0
3 years ago
The aqueous humor in a person's eye is exerting a force of 0.242 N on the 1.21 cm2 area of the cornea. What pressure is this in
Virty [35]

Answer:

<h2><em>15.00124mmHg</em></h2>

Explanation:

Pressure is defined as the ratio of force applied to an object to its area.

Pressure = Force/Area

Given parameters

Force = 0.242N

Area = 1.21cm²

Required parameters

Pressure = 0.242/1.21

Pressure = 0.2N/cm²

Using the conversion to convert the pressure to mmHg

1N/cm² = 75.0062mmHg

0.2N/cm² = y

y = 0.2 * 75.0062

y = 15.00124mmHg

<em>Hence the pressure in mmHg is 15.00124mmHg</em>

4 0
3 years ago
Arrow_forward
garri49 [273]

Explanation:

(a) Hooke's law:

F = kx

7.50 N = k (0.0300 m)

k = 250 N/m

(b) Angular frequency:

ω = √(k/m)

ω = √((250 N/m) / (0.500 kg))

ω = 22.4 rad/s

Frequency:

f = ω / (2π)

f = 3.56 cycles/s

Period:

T = 1/f

T = 0.281 s

(c) EE = ½ kx²

EE = ½ (250 N/m) (0.0500 m)²

EE = 0.313 J

(d) A = 0.0500 m

(e) vmax = Aω

vmax = (0.0500 m) (22.4 rad/s)

vmax = 1.12 m/s

amax = Aω²

amax = (0.0500 m) (22.4 rad/s)²

amax = 25.0 m/s²

(f) x = A cos(ωt)

x = (0.0500 m) cos(22.4 rad/s × 0.500 s)

x = 0.00919 m

(g) v = dx/dt = -Aω sin(ωt)

v = -(0.0500 m) (22.4 rad/s) sin(22.4 rad/s × 0.500 s)

v = -1.10 m/s

a = dv/dt = -Aω² cos(ωt)

a = -(0.0500 m) (22.4 rad/s)² cos(22.4 rad/s × 0.500 s)

a = -4.59 m/s²

3 0
3 years ago
A car travels west at 40 km/h
Nesterboy [21]

Answer:

The car is going 0 km/h more than the bike

Explanation:

3 0
3 years ago
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