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Nesterboy [21]
3 years ago
8

water at 20c discharges from a stroke tank through a 150m length of horizontal pipe. The pipe is smooth and has a diameter of 75

mm. The entrance of the pipe is square edged. What is depth of water needed to produce a volumetric flow rate of .1m3/s
Engineering
1 answer:
inessss [21]3 years ago
7 0

Answer:

The dept of the water needed is 26.11m

Explanation:

Given the following parameters:

Length of the pipe = 150m

Diameter of the pipe = 75mm = 0.75m

Volumetric flow rate 1m^{3}/s

Knowing that:

Volumetric flowrate = area (A) * Velocity(V)

==> 0.1 = A*V                              *Knowing that V = \sqrt{2gh}

==> 0.1  = \frac{\pi }{4}* (0.075)^{2} * \sqrt{2gh}

==> h = 26.11m

Hence, the dept of water needed to produce a volumetric flow rate of 1m^{3}/s is 26.11m.

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Answer:d

Explanation:

Given

Temperature=200^{\circ}\approc 473 K

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(a)1000 km/h\approx 277.78 m/s

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(b)500 km/h\approx 138.89 m/s

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Mach no.=1.27

(d)200 km/h\approx 55.55 m/s

Mach no.=\frac{55.55}{\sqrt{1.4\times 287\times 473}}

Mach no.=0.127

From above results it is clear that for Flow at velocity 200 km/h ,it will be incompressible.

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Answer:

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