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PIT_PIT [208]
3 years ago
12

A 10-mm-diameter Brinell hardness indenter produced an indentation 2.50 mm in diameter in a steel alloy when a load of 1000 kg w

as used. Calculate the HB of this material.
Engineering
1 answer:
zysi [14]3 years ago
4 0

Answer:

HB \approx 200.484

Explanation:

The Brinell Hardness is obtained from the following formula:

HB = \frac{2\cdot P}{\pi \cdot D^{2}}\cdot \left(\frac{1}{1 - \sqrt{1-\frac{d^{2}}{D^{2}} } } \right )

Where P is the load measured in kilograms-force, D is the diameter of indenter measured in millimeters and d is the diameter of indentation measured in millimeters.

HB=\frac{2\cdot (1000\,kgf)}{\pi\cdot (10\,mm)^{2}}\cdot \left[ \frac{1}{1-\sqrt{1-\frac{(2.50\,mm)^{2}}{(10\,mm)^{2}} } }  \right ]

HB \approx 200.484

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