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ruslelena [56]
2 years ago
14

5. A 15-nC point charge is at the origin in free space. Calculate V₁ if point P, is located at

Engineering
1 answer:
Gala2k [10]2 years ago
6 0
I don’t know lm so sorry
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11Alexandr11 [23.1K]

I think the orange thing on the gun but i dont know what principle it is but i think its c

Explanation:

Whem you press the orange thing it starts to work

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3 years ago
Elements in the same ____ have the same numbers of valence electrons?
lions [1.4K]
Explanation: For main group elements, the number of valence electrons is the same in every element in the same group. Group 1 elements have 1 valence electron in the s orbital.
8 0
3 years ago
Read 2 more answers
What unit of measurment would be used to measure current?
Alex_Xolod [135]

Answer:

The S. I unit of current is Amphere

5 0
4 years ago
Water at atmospheric pressure boils on the surface of a large horizontal copper tube. The heat flux is 90% of the critical value
zloy xaker [14]

Answer:

119.1°c

Explanation:

Temperature can be referred to as a measure of the warmth or coldness of an object or substance with reference to some standard value. The temperature of two systems is the same when the systems are in thermal equilibrium.

To determine the tube surface temperature immediately after installation and after prolonged service.

We will apply to appropriate formula, but first lets define the terms in the question.

Please kindly check attachment.

6 0
4 years ago
A large class with 1,000 students took a quiz consisting of ten questions. To get an A, students needed to get 9 or 10 questions
VMariaS [17]

Answer:

a. 0.11

b. 110 students

c. 50 students

d. 0.46

e. 460 students

f. 540 students

g. 0.96

Explanation:

(See attachment below)

a. Probability that a student got an A

To get an A, the student needs to get 9 or 10 questions right.

That means we want P(X≥9);

P(X>9) = P(9)+P(10)

= 0.06+0.05=0.11

b. How many students got an A on the quiz

Total students = 1000

Probability of getting A = 0.11 ---- Calculated from (a)

Number of students = 0.11 * 1000

Number of students = 110 students

So,the number of students that got A is 110

c. How many students did not miss a single question

For a student not to miss a single question, then that student scores a total of 10 out of possible 10

P(10) = 0.05

Total Students = 1000

Number of Students = 0.05 * 1000

Number of Students = 50 students

We see that 5

d. Probability that a student pass the quiz

To pass, a student needed to get at least 6 questions right.

So we want P(X>=6);

P(X>=) =P(6)+P(7)+P(8)+P(9)+P(10)

=0.08+0.12+0.15+0.06+0.05=0.46

So, the probability of a student passing the quiz is 0.46

e. Number of students that pass the quiz

Total students = 1000

Probability of passing the quiz = 0.46 ----- Calculated from (d)

Number of students = 0.46 * 1000

Number of students = 460 students

So,the number of students that passed the test is 460

f. Number of students that failed the quiz

Total students = 1000

Total students that passed = 460 ----- Calculated from (e)

Number of students that failed = 1000 - 460

Number of students that failed = 540

So,the number of students that failed is 540

g. Probability that a student got at least one question right

This means that we want to solve for P(X>=1)

Using the complement rule,

P(X>=1) = 1 - P(X<1)

P(X>=1) = 1 - P(X=0)

P(X>=1) = 1 - 0.04

P(X>=1) = 0.96

7 0
3 years ago
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