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Eva8 [605]
3 years ago
14

A lead fishing weight with a mass of 57 g absorbs 146 cal of heat If its initial temperature is 48 ∘C, what is its final tempera

ture?
Chemistry
2 answers:
irga5000 [103]3 years ago
5 0

<u>Answer:</u>

<em>132 ℃ is the final temperature.</em>

<em></em>

<u>Explanation:</u>

Q = m \times c \times \Delta T

where ∆T =final T- initial T

Q is the heat energy in calories = 146cal

c is the specific heat capacity

(for Lead (0.128 J/(g℃)) or (0.0305 cal/(g℃)  

m is the mass of lead = 57g

Initial temperature is 48℃

Plugging in the values  

146cal = 57g × 0.0305 cal/(g℃) × (final T - 48℃)

\frac {146cal}{(57g\times0.0305 cal/(g℃))} = final T-48^\circ{C}

83.98℃ = final T - 48℃

So,

Final T = 83.98℃ + 48℃

Final T = 131.98℃ = 132℃ (Answer)

Vikentia [17]3 years ago
3 0

Answer:

The final temperature is 130.6°, at the end of the process.

Explanation:

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