Answer:
The fraction of the protons would have no electrons 
Explanation:
We are given that
Amoeba has total number of protons=
Net charge, Q=0.300pC
Electrons are fewer than protons=
We have to find the fraction of protons would have no electrons.
The fraction of the protons would have no electrons
=
The fraction of the protons would have no electrons
=

Hence, the fraction of the protons would have no electrons 
<span>The answer is C. This is called polarization of light by reflection. The sunlight is reflected at a parallel angle from on the surface plane of the water from which it bounces from. The glare is due to this polarization of sun beams at an angle with respect to the viewer. </span>
Answer:
KE = 0.162 KJ
Explanation:
given,
mass of bullet (m)= 20 g = 0.02 Kg
speed of the bullet (u)= 1000 m/s
mass of block(M) = 1 Kg
velocity of bullet after collision (v)= 100 m/s
kinetic energy = ?
using conservation of momentum
m u = m v + M V
0.02 x 1000 = 0.02 x 100 + 1 x V
20 = 2 + V
V = 18 m/s
now,
Kinetic energy of the block


KE = 162 J
KE = 0.162 KJ
Given that in a parallel circuit:
R1 = 12 ohms
R2= 15 ohms
I = 12 A
I2 = 4 A
V=?
R=?
R3 =?
P=?
Since,
V= IR
or,
V2 = I2 * R2
V2= 4* 15
V2 = 60V
Since in a parallel circuit voltage remain same in all component of the circuit and is equal to the source voltage.
Therefore,
V= V1 = V2 = V3 = 60V
Since,
V= IR
R= V/I
R= 60/12
R= 5 ohm
That is total resistance is equal to 5 ohms.
Since for parallel circuit,
1/R= 1/R1 + 1/R2 + 1/R3
1/5= 1/12+ 1/15 + 1/R3
or
1/R3= 1/5- 1/12- 1/15
1/R3= 1/20
or
R3= 20 ohms
Since,
V=IR
I= V/R
I1= V1/ R1
I1= 60/12
I1= 5 A
I3= V3/R3
I3= 60/20
I3= 3A
Since,
P=VI
P= 60*12
P= 720 watt
P1= V1* I1
P1= 60* 5
P1= 300 watt
P2= V2* I2
P2= 60* 4
P2= 240watt
P3= V3*I3
P3= 60*3
P3= 180 watt
Hence we have,
R1= 12 ohms , R2= 15 ohms, R3= 20 ohms, R= 5 ohms
I1= 5A, I2= 4A, I3= 3A, I= 12 A
V1= V2= V3= V= 60V
P1= 300 watt, P2= 240 watt, P3 = 180 watt, P= 720 watt