Two parallel wires carry a current I in the same direction. Midway between these wires is a third wire, also parallel to the oth
er two, which carries a current 0.5 I, but in the direction opposite from the first two wires. Two more wires with 0.5 I, in the same direct as the third wire, are placed the same distance as the third wire but on either side of the first two wires. In which direction are the net forces on the outer wires?
2 answers:
Answer:
[ Find the attached file ]
First i draw a figure showing the condition, I had taken attractive force as +ve and repulsive force as - ve and thereafter calculating net force on outer left wire due to other wires, net force comes out to be - ve which tells us that force is repulsive, hence direction of force is away from wire as shown in figure.
Answer:
Force is repulsive hence direction of force is away from wire
Explanation:
The first thing will be to draw a figure showing the condition,
Lets takeI attractive force as +ve and repulsive force as - ve and thereafter calculating net force on outer left wire due to other wires, net force comes out to be - ve which tells us that force is repulsive, hence direction of force is away from wire as shown in figure in the attachment.
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(a) The screen is 3.20m from the split.
(b) The closest minima for green, distance Δy = 0.45 cm.
When a wave hits a barrier or opening, numerous events are referred to as diffraction. It is described as the interference or bending of waves via an aperture or around the corners of an obstruction into the area that forms the geometric shadow of the obstruction or aperture.
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Question
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