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Stella [2.4K]
3 years ago
11

If the weight of 1kg is 10 N in water what is the density of the stone​

Physics
1 answer:
vekshin13 years ago
5 0

Answer:

I have a screenshot of this.

Explanation:

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Assume that a person bouncing a ball represents a closed system. Which statement best describes how the amounts of the ball's po
Zinaida [17]

Answer:

C.

Explanation:

7 0
3 years ago
You are pulling a child in a wagon. The rope handle is inclined upward at a 60∘ angle. The tension in the handle is 20 N.How muc
ahrayia [7]

Work is equal to the force applied times the displacement. Since you pull the wagon at constant speed this means that there is no acceleration on the wagon as it does not change speed. F=ma. Since a=0, F=0. Therefore no work has been done in this situation

3 0
3 years ago
two skateboarders of mass 50 kg and 60 kg push each other with force 70N.what is the acceleration of each skaters.step by step.
Keith_Richards [23]

Answer:

f=ma

f=70N

m1=50kg

m2= 60kg

a1= f/m

a1= 70/50

a1= 1.4N/kg

a2= 70/60

a2=1.17N/kg

6 0
3 years ago
You need to remove a broken light bulb from a lamp. without a pair of gloves, you are likely to cut yourself on the jagged glass
mojhsa [17]
<span>You have just demonstrated an insight learning. Internal insight occurs if one learned a new way without the help of environmental factors. In here, what the person initially learned that if one saw a broken light bulb from a lamp, he can be cut through the jagged glass if one does not wear a pair of gloves. And maybe because at the moment, the person could not find one, he felt using a cut potato to pick up the pieces of the broken lamp. This is a demonstration of insight learning. The person found a way to pick up the pieces of the broken lamp by using his instinct at the moment. The person is not influenced by an outside source to tell him to use a potato. </span>
5 0
3 years ago
A 1.00 kg object is attached to a horizontal spring. the spring is initially stretched by 0.500 m, and the object is released fr
valina [46]
The  spring is initially stretched, and the mass released from rest (v=0). The next time the speed becomes zero again is when the spring is fully compressed, and the mass is on the opposite side of the spring with respect to its equilibrium position, after a time t=0.100 s. This corresponds to half oscillation of the system. Therefore, the period of a full oscillation of the system is
T=2 t = 2 \cdot 0.100 s = 0.200 s
Which means that the frequency is
f= \frac{1}{T}= \frac{1}{0.200 s}=5 Hz
and the angular frequency is
\omega=2 \pi f = 2 \pi (5 Hz)=31.4 rad/s

In a spring-mass system, the maximum velocity of the object is given by
v_{max} = A \omega
where A is the amplitude of the oscillation. In our problem, the amplitude of the motion corresponds to the initial displacement of the object (A=0.500 m), therefore the maximum velocity is
v_{max} = A \omega = (0.500 m)(31.4 rad/s)= 15.7 m/s
6 0
3 years ago
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