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Leokris [45]
3 years ago
5

Starting from rest, a coin and a ring roll down a ramp without slipping. Which of the following are true:

Physics
1 answer:
svetlana [45]3 years ago
4 0

Answer:

The answer is D

Explanation:

The object with the heavy mass will reach first because the cause it is heaver so it will go faster

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A flywheel with a diameter of 1.63 m is rotating at an angular speed of 79.9 rev/min. (a) What is the angular speed of the flywh
Studentka2010 [4]

Answer:

(a) 8.362 rad/sec

(b) 6.815 m/sec

(c) 9.446 rad/sec^2

(d) 396.22 revolution

Explanation:

We have given that diameter d = 1.63 m

So radius r=\frac{d}{2}=\frac{1.63}{2}=0.815m

Angular speed N = 79.9 rev/min

(a) We know that angular speed in radian per sec

\omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 79.9}{60}=8.362rad/sec

(b) We know that linear speed is given by

v=r\omega =0.815\times 8.362=6.815m/sec

(c) We have given final angular velocity \omega _f=675rev/min

And \omega _i=79.9rev/min

Time t = 63 sec

Angular acceleration is given by \alpha =\frac{\omega _f-\omega _i}{t}=\frac{675-79.9}{63}=9.446rad/sec^2

(d) Change in angle is given by

\Theta =\frac{1}{2}(\omega _i+\omega _f)t=\frac{1}{2}(675+79.9)\times 1.05=396.22rev

7 0
3 years ago
A............... pulley helps us by changing the direction of the applied effort​
DerKrebs [107]

Explanation:

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8 0
3 years ago
Read 2 more answers
car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of a. The car
Luba_88 [7]

Answer:

0.572

Explanation:

First examine the force of friction at the slipping point where Ff = µsFN = µsmg.

the mass of the car is unknown,

The only force on the car that is not completely in the vertical direction is friction, so let us consider the sums of forces in the tangential and centerward directions.

First the tangential direction

∑Ft =Fft =mat

And then in the centerward direction ∑Fc =Ffc =mac =mv²t/r

Going back to our constant acceleration equations we see that v²t = v²ti +2at∆x = 2at πr/2

So going backwards and plugging in Ffc =m2atπr/ 2r =πmat

Ff = √(F2ft +F2fc)= matp √(1+π²)

µs = Ff /mg = at /g √(1+π²)=

1.70m/s/2 9.80 m/s² x√(1+π²)= 0.572

7 0
3 years ago
How far will a rubber ball fall in 10 seconds?
Inessa [10]

If it's not moving at all at the beginning of the 10 seconds, then it falls 490 meters straight down in 10 seconds.

(Note: This is true of all objects on Earth . . . rubber balls, feathers, grains of sand, school buses, battle ships . . . everything.  As long as air doesn't hold them back.  Anything falling from rest falls 490 meters in the first 10 seconds.)

4 0
3 years ago
Who has the greater velocity, an astronaut who has just completed an orbit of the Earth or you when you have just traveled from
Alik [6]

Answer:

the answer is

Explanation:

constant acceleration

because when the object's velocity is changing then the object is accelerating or decelerating

as acceleration describe changing of velocity so the answer is constant acceleration

Acceleration is defined as the rate of change of velocity.

Acceleration = (Change in velocity) / time taken

Acceleration = (Final velocity - initial velocity) / time

As the object velocity changes by the same amount in each second, it means the acceleration is constant.

Hope I can help u

4 0
3 years ago
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