Answer:
The value is 
Explanation:
From the question we are told that
The height of the top meter stick above the ground is 
The time taken for the acorn to pass the length of the stick is 
Generally the height of the acorn at the point it is the same height with the metered stick is mathematically represented as
Here 
is height of the meter stick and the value is 1 m (This because we are told in the question that the stick is 1 meter in length ( a meter stick))
So
=> 
Generally the velocity of the acorn just before passing the top of the meter stick is mathematically represented by a kinematic equation as
here u is zero since the acorn started from rest
So
Generally the height of the acorn is
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Answer:
Power of the bulb is 10 Watts.
Explanation:
We have,
Power and voltage of electric bulb is 40 W and 200 V. Using this data we can find the resistance of the bulb.
Power, 
R is resistance
The supplied voltage is 100 V.
Now power is given by :
So, now the power of the bulb is 10 Watts.
According to newton's second law of motion F=ma , but here we have to find a so a=f/m ,a=8.11/1028=0.007m/sec² or 7×10‐3m/sec2
Answer:
Rate = k[aryl halide][nucleophile]
Explanation:
The simple aryl halides are almost inert to usual nucleophilic reagents but considerable activation on the ring can be produced by the addition of strongly electron-attracting substituents on either the ortho or para positions, or both. These groups deactivate the ring to allow the attack of the nucleophille on the ring.
Thus, these reactions can occur by following addition-elimination mechanism in which the nucleophille first attacks the aryl halide and then the elimination of the leaving group takes place.
<u>Kinetic studies of this type of mechanism demonstrate that the reactions are of second-order kinetics– first order w.r.t. nucleophile and also, first-order w.r.t. aromatic substrate. The rate determining step (r.d.s.) is the formation of the addition intermediate.</u>
Thus,
<u>Rate = k[aryl halide][nucleophile]</u>
Answer:
Explanation:
An impulse results in a change of momentum
If the wagon and dog both stop, they must have had equal and opposite momentums
FΔt = mΔv
F = mΔv/Δt = m(v₁ - v₀)/(t₁ - t₀)
v₁ = t₀ = 0
F = m(v₀)/t₁
F = 55(2.1)/0.1 = 1155 N
We could have also figured the dog's initial velocity and used the dog's mass in the equation as well. Result would be identical.
