the student determines the molar mass of the gas to be 64 g mol-1. write the expression (set-up) for calculating the percent err

Question

3 years ago

6

or in the experimental value, assuming that the unknown gas is butane (molar mass 58 g mol-1). calculations are not required

1 answer:

sleet_krkn [62] · Answer 1 · 2021-12-31T07:29:01+03:00

Answer:

Percentage error = $\frac{(64 - 58)}{58}$ x 100%

Explanation:

In order to calculate the percentage error in the student's calculation, the following formula will be used:

Percentage error = $\frac{(experimental molar mass - theoretical molar mass)}{theoretical molar mass}$ x 100%

experimental molar mass = 64 g/mol

theoretical molar mass = 58 g/mol

Hence, the expression becomes:

Percentage error = $\frac{(64 - 58)}{58}$ x 100%