Answer:
option (C)
Explanation:
EMF stand for electro motive force. the emf of a battery is the potential between the two electrodes when it is not use in the circuit.
The terminal potential difference is the potential difference between the electrodes of a cell when it is in use.
EMF is only when the current is very large in the battery.
Answer:
194 V/m
Explanation:
In order to find electric field, we can use the formula of power density
i.e Pd = E^2 / Z
where:
Pd = power density in W/m^2
E = electric field strength in V/m
Z = impedance of free space = 120 * π
E = sqrt(Pd * Z)
-----> re-arranging it for E
before solving, convert Pd unit into W/m^2
Pd= 5mW/cm^2 = 50 W/m^2
Solving for E:
E= sqrt(50 * 120 * π)
E = 137.3 V/m
the above value is RMS value
In order to find the peak amplitude of the oscillating field will therefore be 137.3 * sqrt(2) = 194 V/m
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Please find attached photograph for your answer.
Answer:
ΔL =0. 000312 m
Explanation:
Given that
At room temperature ( T = 25 ∘C) ,L= 1 m
So the length at 13.0 ∘C above room temperature
L=1.000312 m
So the change in length
ΔL = 1.000312 - 1.0000 m
ΔL =0. 000312 m
