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Studentka2010 [4]
3 years ago
7

At this temperature, 0.400 mol of h2 and 0.400 mol of i2 were placed in a 1.00-l container to react. what concentration of hi is

present at equilibrium?
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
3 0
Kc = [HI]² / {[H2] [I2]}
53.3 = (2x)² / {(0.400M - x)(0.400M - x)}
sqrt(53.3) = 2x / (0.400M - x)
2.92 - 7.30x = 2x
x = 0.314M

[HI] = 2x = 0.628M
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