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Studentka2010 [4]
3 years ago
7

At this temperature, 0.400 mol of h2 and 0.400 mol of i2 were placed in a 1.00-l container to react. what concentration of hi is

present at equilibrium?
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
3 0
Kc = [HI]² / {[H2] [I2]}
53.3 = (2x)² / {(0.400M - x)(0.400M - x)}
sqrt(53.3) = 2x / (0.400M - x)
2.92 - 7.30x = 2x
x = 0.314M

[HI] = 2x = 0.628M
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Answer:

See explanation

Explanation:

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1. Potassium hydroxide and sulfuric acid react to produce potassium sulfate salt and water.

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<h3>Further explanation</h3>

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

453.9 mL  of 0.237 M calcium acetate

  • mol

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  • mass

MW Ca(C₂H₃OO)₂ : 158,17 g/mol

\tt mass=mol\times MW\\\\mass=0.108\times 158.17=17.082~g

4 0
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