Answer:
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Explanation:
question 1
moles = mass/molar mass of Al(OH)3
convert Kg to g
that is 1.09 x 1000=1090g
moles is therefore=1090g/78(molar mass of Al(OH)3)= 13.974 moles
question 2
moles=2.55g/327.2(molar mass of Pb(CO3)2= 7.79 x 10^-3 moles
from avogadro constant
1moles=6.02 x10^23 formula units
what about 7.79 x 10 ^-3
={(7.79 x 10^-3)moles x ( 6.02 x10^23)} /1 mole=4.69 x10^21 formula units
Answer:
-36.67 KJ
Explanation:
Now, we ,must find the E°cell as follows;
E°cell= E°cathode - E°anode
E°cathode= -0.25 V
E°anode = - 0.44 V
E°cell= -0.25 -(- 0.44) = 0.19 V
Equation of the reaction; Ni2+ (aq) + Fe(s) → Ni(s) +Fe2+ (aq)
Hence, n=2, there were two electrons transferred.
ΔG=-nFE°cell
ΔG= -(2 * 96,500 * 0.19)
ΔG= -36670 J
ΔG= -36.67 KJ
