What is the mass, in grams, of each elemental sample? a. 2.3 * 10-3 molSb b. 0.0355 mol Ba c. 43.9 mol Xe d. 1.3 mol W
1 answer:
Answer:
a. Sb =0.280048 g , b. Ba=4.875215 g , c. Xe=5763.631 g , d. W=238.992 g
Explanation:
number of moles =
(a) For Sb, molar mass =121.76g/mol
number of moles =2.3*mol
<em>mass= number of moles * molar mass</em>
mass =2.3* *121.76
mass =0.280048 g
(b) for Ba, molar mass=137.33 g/mol
number of moles =0.0355 mol
mass = 0.0355 *137.33
mas = 4.875215 g
(c) for Xe, molar mass = 131.29 g/mol
number of moles =43.9 mol
mass =43.9 *131.29
mass =5763.631 g
(d) for W, molar mass = 183.84 g/mol
number of moles = 1.3mol
mass = 1.3 *183.84
mass = 238.992 g
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Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy